The answer is B
A number line from negative 8 to positive 8 in increments of 1, with only whole numbers that are multiples of 2 labeled. Place point P at the third tick mark to the left of 0. Put point Q at the fifth tick mark to the right of 0.
Answer: ![0.861](https://tex.z-dn.net/?f=0.861%3C%5Cmu%3C%200.865)
Step-by-step explanation:
The confidence interval for population mean
is given by :-
, where n=sample size
= sample mean
=sample standard deviation
= critical t-value (for two tailed )
Let
be the confidence interval for the population mean mercury concentration.
As per given , we have
Sample size : n= 28
degree of freedom = 27 [df=n-1]
Sample mean :
cc/cubic meter
Sample standard deviation : s= 0.0036
Significance level : ![\alpha=1-0.98=0.02](https://tex.z-dn.net/?f=%5Calpha%3D1-0.98%3D0.02)
Critical two-tailed test value :
(Using t-distribution table.)
We assume the population is approximately normal.
Now, the 98% confidence interval for the population mean mercury concentration will be :-
Required confidence interval : ![0.861](https://tex.z-dn.net/?f=0.861%3C%5Cmu%3C%200.865)
3t+2=7, 3t=5, t= 5/3, so the answer is C. 5/3
Answer:
answers and explanation is shown in the attachment
Step-by-step explanation:
The detailed steps and necessary substitution is as shown in the attached files.
Answer:
(4, 10)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties<u>
</u>
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-5y + 8x = -18
5y + 2x = 58
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Combine 2 equations: 10x = 40
- [Division Property of Equality] Divide 10 on both sides: x = 4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em> [Original equation]: -5y + 8(4) = -18
- Multiply: -5y + 32 = -18
- [Subtraction Property of Equality] Subtract 32 on both sides: -5y = -50
- [Division Property of Equality] Divide -5 on both sides: y = 10