Eeeeeeek need help! 5/3w = -10 A. -6 B. -1/6 C. -50/3 D. -5/6

In the 7th grade, 150 of the students are attending the dance. If this is 62.5% of the entire grade, how many 7th graders are th

JulijaS [17]

Answer:

244 students.

Step-by-step explanation:

Okay, so. We know 150 people of the 7th grade is coming and 62.5% is the entire of the 7th graders coming. We would multiply.

150 * 62.5% = 93.75

We would round it up. It is over 5, so it would be 94 students. Then we would add

150 + 94 = 244

There are 244 students in 7th grade.

3 0

3 years ago

I need help i will give brainiest question in screenshot

Thepotemich [5.8K]

Answer:

ok so first you have to know what a reflectiin along 180 is

) A point P(x,y)P(x,y) is rotated 180180 degrees about the origin, then reflected over the y-axis. What is the resulting image of PP?

My conjecture: (−x,y)(−x,y) but I don't quite agree with it graphically. I'm having trouble with what exactly a 180 degree rotation about the origin simply is.

2) A point P(x,y)P(x,y) is reflected over the y-axis and then rotated 180 degrees about the origin. What is the resulting image?

Is this the same thing as 1?

3) A point A(x,y)A(x,y) is reflected over the line y=xy=x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (−y,x)(−y,x)

4) A point A(x,y)A(x,y) is reflected over the lines y=−xy=−x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (y,−x)

ok you need to know what thouse meen

Step-by-step explanation:

)If P(x1,y1)P(x1,y1) is rotated angle ϕϕ about O(a,b)O(a,b) to P′(x′,y′)P′(x′,y′)

we have |OP|=|OP′||OP|=|OP′| and |arctanmOP−arctanmOP'|=ϕ|arctan⁡mOP−arctan⁡mOP'|=ϕ

By atan(z)(z) I imply atan2

(2)If P(x1,y1)P(x1,y1) is reflected over L:ax+by+c=0L:ax+by+c=0 and the resulting image of PP is Q(x2,y2) (1)Q(x2,y2) (1)

We have R

so i hope thiz helprs you

3 0

3 years ago

The manager of a fashionable restaurant open Wednesday through Saturday says that the restaurant does about 29 percent of its bu

RideAnS [48]

Answer: The seasonal relatives is calculated are as follows:

Step-by-step explanation:

Given that,

restaurant only open from Wednesday to Saturday,

29 percent of its business on Friday
31 percent on Saturday night
21 percent on Thursday night.

∴ The remaining 19% of its business he does on Wednesday

Now, suppose that total production of sales in a given week be 'y'

So, average sales in a week = $\frac{y}{4}$

If we assume that y = 1

hence, average sales in a week = $\frac{1}{4}$

= 0.25

Now, we have to calculate the seasonal relatives,

that is,

= $\frac{Sales in a given day}{average sales in a week}$

Wednesday:

= $\frac{0.19}{0.25}$

= 0.76

Thursday:

= $\frac{0.21}{0.25}$

= 0.84

Friday:

= $\frac{0.29}{0.25}$

= 1.16

Saturday:

= $\frac{0.31}{0.25}$

= 1.24

8 0

3 years ago

You roll two number cubes. What is the probability of rolling double threes?

AURORKA [14]

2/36 or 5.55...%(repeated 5).

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%20%5Crm%20%20%5Clim_%7Bk%20%5Cto%20%5Cinfty%20%7D%20%5Csqrt%5B%20%20k%5D%7B%20%5CGamma%20%

Naddik [55]

We have

$\sqrt[k]{\Gamma\left(\dfrac1k\right) \Gamma\left(\dfrac2k\right) \cdots \Gamma\left(\dfrac kk\right)} \\\\ = \exp\left(\dfrac{\ln\left(\Gamma\left(\dfrac1k\right) \Gamma\left(\dfrac2k\right) \cdots \Gamma\left(\dfrac kk\right)\right)}k\right) \\\\ = \exp\left(\dfrac{\ln\left(\Gamma\left(\dfrac1k\right)\right)+\ln\left( \Gamma\left(\dfrac2k\right)\right)+ \cdots +\ln\left(\Gamma\left(\dfrac kk\right)\right)}k\right)$

and as k goes to ∞, the exponent converges to a definite integral. So the limit is

$\displaystyle \lim_{k\to\infty} \sqrt[k]{\Gamma\left(\dfrac1k\right) \Gamma\left(\dfrac2k\right) \cdots \Gamma\left(\dfrac kk\right)} \\\\ = \exp\left(\lim_{k\to\infty} \frac1k \sum_{i=1}^k \ln\left(\Gamma\left(\frac ik\right)\right)\right) \\\\ = \exp\left(\int_0^1 \ln\left(\Gamma(x)\right)\, dx\right) \\\\ = \exp\left(\dfrac{\ln(2\pi)}2}\right) = \boxed{\sqrt{2\pi}}$

6 0

2 years ago