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worty [1.4K]
3 years ago
9

Write the numerical

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

(2+5)10-5=65 is the answer

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A box contains five ping-pong balls, each with a number written on it. One ball has a one painted on it, one ball has a four, tw
Temka [501]

Answer:

0

Step-by-step explanation:

Numbers on balls:

1, 4, 7, 7, 8

Try to find the sum of all numbers:

1+4+7+7+8 = 27

According to the rule of 3, any number is dividable by 3 if the sum of it's individual is divided by 3.

27 is dividable by 3, therefore any combination will result a number with a factor of three.

Prime number is the number that is only dividable by 1 and itself. Therefore, any combination using those numbers are not prime number.

So the probability is 0

4 0
3 years ago
Solve 3[-x + (2 x + 1)] = x - 1.
Viktor [21]
The answer is -1. First you distribute the 3. Then u distribute the 3 again to the parentheses. Then solve it from there

4 0
3 years ago
Please help me please I’m being timed
pshichka [43]

Answer:

point symmetry if no symmetry isn't an option as it looks grayed out and not clickable

5 0
1 year ago
Which expression is equal to 5^4⋅5^8 ? 512 54 52 5−4
KiRa [710]

Answer is 5^12 which is choice A (assuming you meant to put the ^ symbol)

The bases are the same (both are 5), so you add the exponents: 4+8 = 12. The base stays the same the entire time.

So, 5^4*5^8 = 5^(4+8) = 5^12

3 0
3 years ago
The ages of two brothers are in the ratio two to three, but in eight years, the ratio of their ages will be three to four. What
Darina [25.2K]
X = older brother
y = younger brother 

Equation 1: x/y = 2/3 ⇒ x = 2y/3
Equation 2: x + 8/y + 8 = 3/4

( \frac{2y}{3} + 8) / y +8 =  \frac{3}{4}
(2y + 24)/3 = y + 8 =  \frac{3}{4}
2y + 24 = 3 (y + 8) =  \frac{3}{4}
2y + 24 = 3y + 24 =  \frac{3}{4}
4 (2y + 24) = 3 (3y + 24)
8y + 96 = 9y + 72
y = 24

The age of the older brother is 24.

x =  \frac{2y}{3} = \frac{2*24}{3}
x =  \frac{48}{3}
x = 16

The age of the youngest brother is 16.
5 0
3 years ago
Read 2 more answers
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