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Morgarella [4.7K]

3 years ago

12

the cafeteria has 2 cases of tuna and 6 single cans of tuna. in all, there are 75 cans of tuna. How many cans of tuna are in a c

ase

2 answers:

Nastasia [14]3 years ago

7 0

Answer:63

Step-by-step explanation:

andreyandreev [35.5K]3 years ago

5 0

I think it may be 63?

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A cake decorator rolls a piece of stiff paper to form a cone. She cuts off the tip of the cone and uses it as a funnel to pour d

Nimfa-mama [501]

Answer:

Step-by-step explanation:

Use the formula for volume of a cone

V = 1/3 pi r^2 (h)

V = 1/3 pi 66^2 (18)

V= 1/3 pi 4356(18)

V = 1/3 pi 78408

V = 1/3 264,201.12

V = 82,067.04cm^3

5 0

3 years ago

Please help me to prove this!

Sophie [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B = C → A = C - B

→ B = C - A

Use the Double Angle Identity: cos 2A = 2 cos² A - 1

→ (cos 2A + 1)/2 = cos² A

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · 2 cos [(A - B)/2]

Use Even/Odd Identity: cos (-A) = cos (A)

<u>Proof LHS → RHS:</u>

LHS: cos² A + cos² B + cos² C

$\text{Double Angle:}\qquad \dfrac{\cos 2A+1}{2}+\dfrac{\cos 2B+1}{2}+\cos^2 C\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg(2+\cos 2A+\cos 2B\bigg)+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\dfrac{1}{2}\bigg(\cos 2A+\cos 2B\bigg)+\cos^2 C$

$\text{Sum to Product:}\quad 1+\dfrac{1}{2}\bigg[2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A-2B}{2}\bigg)\bigg]+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\cos (A+B)\cdot \cos (A-B)+\cos^2 C$

$\text{Given:}\qquad \qquad 1+\cos C\cdot \cos (A-B)+\cos^2C$

$\text{Factor:}\qquad \qquad 1+\cos C[\cos (A-B)+\cos C]$

$\text{Sum to Product:}\quad 1+\cos C\bigg[2\cos \bigg(\dfrac{A-B+C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+(C-B)}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-(C-A)}{2}\bigg)$

$\text{Given:}\qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+A}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-B}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1+2\cos C \cdot \cos A\cdot \cos (-B)$

$\text{Even/Odd:}\qquad \qquad 1+2\cos C \cdot \cos A\cdot \cos B\\\\\\.\qquad \qquad \qquad \quad =1+2\cos A \cdot \cos B\cdot \cos C$

LHS = RHS: 1 + 2 cos A · cos B · cos C = 1 + 2 cos A · cos B · cos C $\checkmark$

5 0

3 years ago

Do birds And dogs reincarnate

vovangra [49]

Answer:

no

Step-by-step explanation:

4 0

4 years ago

HELP PLS<br> Solve for x<br> x=[?]<br> 3x + 2 6x - 20

Sloan [31]

Step-by-step explanation:

Remember that the sum of angles on a straight line are supplementary. (180°)

Therefore 3x + 2 + 6x - 20 = 180.

=> 9x - 18 = 180

=> 9x = 198

=> x = 22.

3 0

3 years ago

HELP 1-6 ME PLEASE (35 POINTS)

makvit [3.9K]

1. $1.90
5. $2.74
6. $2.25

7 0

3 years ago