1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Morgarella [4.7K]
3 years ago
12

the cafeteria has 2 cases of tuna and 6 single cans of tuna. in all, there are 75 cans of tuna. How many cans of tuna are in a c

ase
Mathematics
2 answers:
Nastasia [14]3 years ago
7 0

Answer:63


Step-by-step explanation:


andreyandreev [35.5K]3 years ago
5 0
I think it may be 63?
You might be interested in
What are the solutions to the quadratic equation 0=(x−4)(x+2)?
Alex777 [14]

Answer:

x = 4,

x = -2

Step-by-step explanation:

( x - 4 ) ( x + 2 ) = 0

Find out when the equation is 0,

When x = 4,

substitute in 4 for x,

( 4 - 4 ) ( 4 + 2 ) = 0

(0) ( 6) = 0 (any number multiplied by 0 is 0).

When x = -2

Substitue in -2 for x,

( -2 - 4 ) ( -2 + 2 ) = 0

(-6) (0) = 0 (again, any number multiplied by 0 is 0).

4 0
3 years ago
Read 2 more answers
Multiply. Express in simplest form. 3/8 x 1/2
CaHeK987 [17]

Answer:

the answer is 3/16.

Step-by-step explanation:

First, let's take a look at the expression itself.

We have to multiply 3/8 and 1/2, which gives us the expression of

3/8*1/2

then, we multiply the numerator by the numerator and get 3, then we multiply the denominator by the other denominator which gets us 16. We put the two parts together and get

3/16

which is not simplifiable. So 3/16 is the simplest answer we can get.

5 0
3 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
Afina-wow [57]

Answer:

\large \boxed{\textbf{30.54 yr}}

Step-by-step explanation:

For species A,

P =2000e^{0.05t}

For species B,

P =5000e^{0.02t}

When their populations are equal,

\begin{array}{rcl}2000e^{0.05t} & = & 5000e^{0.02t}\\e^{0.05t} & = & 2.5e^{0.02t}\\0.05t & = & \ln2.5 + 0.02t\\0.05t & = & 0.9163 + 0.02t\\0.03t & = & 0.9163\\t& = & \dfrac{0.9163}{0.03}\\\\& = & \mathbf{30.54}\\\end{array}\\\text{The populations of species A and B will be the same in $\large \boxed{\textbf{30.54 yr}}$}

The diagram below shows the population of Species A overtaking that of Species B in about 30.5 yr.

3 0
4 years ago
Ed's new car has a value of $23,500, but it is expected to depreciate at a rate of 7.5% per year. If you were to write an expone
Delicious77 [7]

Answer:

0.925 or 92.5%

Step-by-step explanation:

y=a(1-b)^x

decay factor is 1-b <- and the part we care about

b is 7.5%=0.075

1-0.075

=0.925

I'm a little rusty on exponential rates, but I hope this helps!

3 0
3 years ago
Model and solve the following<br>equations:<br>3x +3 = 2x + 7<br>5x + 2 = 3x = 12<br>​
Thepotemich [5.8K]

hope it helps you!!!!!!!!!!

4 0
3 years ago
Other questions:
  • A grocery store has 5 pounds of granola. One customer buys 2/3 pound of granola and another buys 5/6 pound. After these purchase
    6·1 answer
  • Boatesville is a 65 3/5 -kilometer drive from stanton. A bus traveling from stanton to boatesville is 24 1/3 kilometers from boa
    14·2 answers
  • 2x^3 x 8x^8<br><br> write the product in simplest form
    8·1 answer
  • How many digits will be in the quotient of 588 divided by 6 use place value to explain
    10·2 answers
  • Find a rational approximation for the edge lengths given as radical expressions for the rectangular prism. Which is the BEST est
    6·1 answer
  • I can’t find the answer to this question please help me!
    14·1 answer
  • Ok Ben runs at 7 metres per second. He runs 210 metres. How<br> long does it take him?
    8·1 answer
  • 1. Based on the construction below, which conclusion
    10·1 answer
  • There are 12 boys and 12 girls in Trevor's math class. His teacher will randomly select one student to present a homework proble
    11·1 answer
  • Best and correct answers gets most brainliest, good luck! :) Wrong answers will be flagged.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!