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Sever21 [200]
3 years ago
14

Which linear inequality is shown on the graph?

Mathematics
2 answers:
ioda3 years ago
5 0

Answer:

Option A

Step-by-step explanation:

The given graph is a solid line passing through two points ( -4, 0) and ( 0, -1 )

Let the equation of this line is y = mx+c

Where m = slope of the line = \frac{y-y'}{x-x'}

              = \frac{0+1}{-4-0} = -(\frac{1}{4})

and y-intercept c = (-1)

therefore, equation will be y = ((\frac{-1}{4}))x + (-1)

                                            y = (\frac{-x}{4}-1

                                           4y = -x -4

                                           x + 4y = -4

Since shaded region is above the line therefore inequality will be (x+4y ≥ -4)

Option A is the answer.

lutik1710 [3]3 years ago
4 0
<span><span>Make it a solid line for y≤ or y≥, and a dashed line for y< or y>
</span><span>Shade above the line for a "greater than" (y> or y≥) 
or below the line for a "less than" (y< or y≤).

So, the answer is A) </span></span><span>x + 4y ≥ −4 

</span><span>x + 4y ≥ −4 
4y </span>≥ -x - 4
y ≥ -x/4 - 1
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