Answer:
Yes
Step-by-step explanation:
First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.
It has mean μ= np = 30×0.56=16.8
standard deviation s = √npq
sqrt(30×0.56×(1-0.56)) = 2.71
So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.
Answer:
6/54 or 1/9
Step-by-step explanation:
6/54 reduces to 1/9
hope this helps
Y=-4x+3-x because if it's -y=4-3+x y is not alone so you need to make y positive and switch the rest of the operations so it can be y=-4+3-x
T≤3
remember that this symbol means less than or equal to
