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Tanzania [10]
4 years ago
13

Please give the answer fast .I will mark you as brainliest.​​

Mathematics
1 answer:
DochEvi [55]4 years ago
8 0

Answer:

1. 5 x3 x1

2. 5

Step-by-step explanation:

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Which of the following is equal to 4/7 x 14/3
icang [17]
4/7 • 14/3 = 56/21 = 2 14/21
4 0
3 years ago
A town planner wants to build two new streets, Elm Street and Garden Road, to connect parallel streets Maple Drive and Pine Aven
Minchanka [31]

Answer:

72

Step-by-step explanation:

Got it right on edg test

4 0
3 years ago
Read 2 more answers
At a concert 5/9 of the people in line are girls. 2/3 are wearing glasses, what fraction of the people are wearing glasses?
Setler79 [48]
The girl bit doesn't really matter except for how it says 5/9 which shows that you should factor it by 3's. If you multiply both the 2 and the 3 in 2/3 you would clearly get 6/9. Which is the same thing but is to get it matching with how the question wrote about the people wearing glasses. 

Answer: 6/9 people
7 0
3 years ago
Multiple choice. Use the Law of Sines to find the missing angle of the triangle. Find m angle C to the nearest tenth if c = 111
nalin [4]

Answer:

Both A and B are possible.

Step-by-step explanation:

It's both!

This is a might tricky. First you have to find the altitude. You have to determine if this is a real triangle.

Sin(22) = opposite / hypotenuse. The hypotenuse = 111. The angle is 22

opposite = hypotenuse * sin(22)

opposite = 111 * sin(22)

opposite = 41.58  and this is the altitude.

What have you learned?

Since 42 is larger than 41.58 you have 2 solutions to the triangle. One of the angles is acute, and the other one is obtuse. They are supplementary angles.

Sin(C) / c = Sin(A) / a

Sin(C) = c * Sin(22) / 42

Sin(C) = 111*sin(22)/ 42

Sin(C) = .99003

Sin(C) = 81.9

So that's your first answer. The second answer comes from Finding the supplement to this angle

supplement + 81.9 = 180

supplement = 180 - 81.9

supplement = 98.1

7 0
3 years ago
Find all possible values of x in the similar triangles pqr stu
antoniya [11.8K]
If triangles PQR and STU are similar then PQ corresponds to ST and PR corresponds to SU. Therefore, PQ/ST=PR/SU
Considering that, PQ= 7-x, ST= 13-x, PR= x²+5 and SU= x² +20
therefore, (7-x)/(13-x)= (x²+5)/(x²+20) 
               cross multiplying,
         7x² +140-x³+20x =13x²+65-x³-5x
combining the like terms,
          6x² +15x -75=0
          solving for x,
    x = 5/2 or -5 
5 0
3 years ago
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