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vovikov84 [41]
3 years ago
6

Open and close ____ immediately following the name of a procedure identify a Visual Basic statement as a procedure call statemen

t.
Computers and Technology
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:  Parentheses

Explanation:

 The open and close parentheses basically identify the visual basic statement   in the procedure call statement.

The close procedure basically in the visual basic statement basically terminate the call of a program that performed the real processing. Open and close is also known as right and left parentheses.

The close statement is basically control the pre-defined programming statement in the particular close procedure.

 

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802.11ac provides an advantage over 802.11n by incorporating increased channel bonding capabilities. What size bonded channels d
bulgar [2K]

Answer:

The 802.11ac wireless standard takes channel bonding to a higher level because it can support 20MHz, 40MHz, and 80MHz channels, with an optional use of 160MHz channels.

Explanation:

The 802.11ac is a standardized wireless protocol established and accepted by the institute of electrical and electronics engineers (IEEE). 802.11ac as a wireless local area network (WLAN) protocol, has multiple amplitude and bandwidth, thus making it to be the first standard wireless protocol to have the ability to operate on a Gigabit (Gb) network.

Generally, the 802.11ac wireless standard provides an advantage over 802.11n by incorporating increased channel bonding capabilities. The 802.11ac wireless standard takes channel bonding to a higher level because it can support 20MHz, 40MHz, and 80MHz channels, with an optional use of 160MHz channels.

<em>On the other hand, 802.11n is a standardized wireless protocol that can support either a 20MHz or 40MHz channel. </em>

6 0
3 years ago
A jackhammer uses pressurized gas to transmit force to the hammer bit. What type of mechanical system is it?
Nadya [2.5K]
This is a pneumatic system
7 0
3 years ago
Write a program that reads 20 integers from the user into an array and uses a function arrayMinimum that accepts an integer arra
neonofarm [45]

Answer:

#include <iostream>

using namespace std;

int arrayMinimum(int myArray[], int myArraySize) {

int small = myArray[0];

for (int i = 0; i < myArraySize; i++) {

   if(myArray[i]<small){

small = myArray[i];

}

 }

 return small;

}

int main(){

   int myArray[20];

   for(int i =0;i<20;i++){

       cin>>myArray[i];          

   }

   cout<<"The smallest is: "<<arrayMinimum (myArray,20);

   return 0;

}

Explanation:

This solution is provided in c++

#include <iostream>

using namespace std;

This line defines the arrayMinimum function

int arrayMinimum(int myArray[], int myArraySize) {

This initializes the smallest of the array element to the first

int small = myArray[0];

This iterates through the array

for (int i = 0; i < myArraySize; i++) {

This if condition checks for the smallest

   if(myArray[i]<small){

The smallest is assigned to the small variable

small = myArray[i];

}

 }

This returns the smallest

 return small;

}

The main method begins here

int main(){

This declares an array of 20 elements

   int myArray[20];

The following iteration allows user input into the array

<em>    for(int i =0;i<20;i++){ </em>

<em>        cin>>myArray[i];          </em>

<em>    } </em>

This calls the method and returns the minimum

   cout<<"The smallest is: "<<arrayMinimum (myArray,20);

   return 0;

}

6 0
2 years ago
Building relationships during your career exploration is called
elena-s [515]
Building relationships during your career exploration is called networking. This is when you are forming relations with those around you so that opportunities may turn up.

Your answer is: Networking 

Have an great day mate!
6 0
3 years ago
Read 2 more answers
Python code 100 Random Numbers (twice)
Leona [35]

import random

i = 1

while i <= 100:

   print("#"+str(i)+": "+str(random.randint(1,100)), end=", ")

   i+=1

print()

i = 1

while i <= 100:

   print("#"+str(i)+": "+str(random.uniform(1,100)), end=", ")

   i += 1

I hope this helps!

8 0
2 years ago
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