The angle m∠AFE is 128 degrees.
<h3>How to find angles?</h3>
∠AFB ≅ ∠EFD
∠EFD = 5x + 6
m∠DFC = (19x - 15)°
m∠EFC = (17x + 19)°
m∠AFE = ?
m∠AFB + m ∠EFD + m∠AFE = 180
Therefore,
5x + 6 + 5x + 6 + m∠AFE = 180
5x + 5x + 6 + 6 + m∠AFE = 180
10x + 12 + m∠AFE = 180
10x + m∠AFE = 180 - 12
10x + m∠AFE = 168
m∠AFE = 168 - 10x
m∠EFC = m ∠EFD + m∠DFC
17x + 19 = 5x + 6 + 19x - 15
17x - 5x - 19x = 6 - 15 - 19
-7x = - 28
x = 28 / 7
x = 4
Therefore,
m∠AFE = 168 - 10x
m∠AFE = 168 - 10(4)
m∠AFE = 168 - 40
m∠AFE = 128°
Therefore, the angle m∠AFE = 128°
learn more on angles here: brainly.com/question/13212279
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Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)=
where
- Me is the margin of error from the mean
- s is the standard deviation of the population
a.
z(p)=
≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)=
≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)=
≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥
where
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥
≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
28 + 18 - pai, <span>atualmente
28+18+18= 64 -soma
64</span>
The answer of the question is b
1. $546.00
2. $180.00
3. $141.38
4. $3762.00
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