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3 years ago

8

The area of a rectangle with base b and height h is bh. A rectangular sports goal is 10 ft wide and 8 ft high. Find the area of

the opening.

1 answer:

Naya [18.7K]3 years ago

5 0

Answer:

$80 (ft)^{2}$

Step-by-step explanation:

As stated in the question, the area of a rectugle is its base by its height.

$A = b*h = 10ft * 8 ft = 80 (ft)^2$

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Last month, 17 people showed up to help a local charity. This month, 55 people volunteered. What is the percentage increase?

astra-53 [7]

Step-by-step explanation:

The formula for percent change is

change/original.

So let's subtract 17 from 55 to find the change. 55-17=38

This is the change. Now we divide it by the original, 17.

38/17=2.235294

We're not done yet! We have to move the decimal point over to the right 2 spaces to make it a percentage. So, the percentage increase is

about 223.53 percent

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3 years ago

Determine the simple interest rate for each given principal, time, and simple interest earned.

Akimi4 [234]

Answer:

31.8%

Step-by-step explanation:

The formula for simple interest is I = PRT, where I = interest earned/paid, P = principal amount deposited or borrowed, R = rate of interest as a decimal, and T = time in years.

I = PRT

5720 = (1200)(R)(15)

5720 = 18,000R

R = 0.3177777, rounded to 31.8%

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2 years ago

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What is the value of p in the equation shown? <br> p3=0.064

Ne4ueva [31]

If you mean the question 3p=0.064 then to find the answer you divide 0.064 by 3 to get 0.213333.....

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2 years ago

How do you reduce ln(3^-e e^3) to simplest form

leva [86]

The logarithm of a product is equal to the sum of logarithms:

$\ln(3^{-e}e^3)=\ln3^{-e}+\ln e^3$

Drop the exponents:

$-e\ln3+3\ln e$

The logarithm of a number is equal to 1 if the base of the logarithm is the same as the number itself:

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3 years ago

Cos^3a-sin^3a/cosa-sina

KIM [24]

Answer:

1 + cosa sina

Step-by-step explanation:

$\frac{cos^3a-sin^3a}{cosa-sina}$

cos³a - sin³a ← is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²) , then

cos³a - sin³a

= (cosa - sina )(cos²a + cosa sina + sin²a)

= (cosa - sina)(1 + cosa sina) [ sin²a + cos²a = 1 ]

Then

$\frac{cos^3a-sin^3a}{cosa-sina}$

= $\frac{(cosa-sina)(1+cosasina)}{cosa-sina}$ ← cancel (cosa - sina) on numerator/ denominator

= 1 + cosa sina

8 0

1 year ago