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3 years ago

8

The area of a rectangle with base b and height h is bh. A rectangular sports goal is 10 ft wide and 8 ft high. Find the area of

the opening.

1 answer:

Naya [18.7K]3 years ago

5 0

Answer:

$80 (ft)^{2}$

Step-by-step explanation:

As stated in the question, the area of a rectugle is its base by its height.

$A = b*h = 10ft * 8 ft = 80 (ft)^2$

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If tñ=2ñ+3, find S10

Allisa [31]

Answer:

$S_{10}=280$

Step-by-step explanation:

Given that,

$t_n=2n+3$ ...(1)

We need to find the value of $S_{10}$ .

Put n = 1 to find the first term.

$t_1=2(1)+3=5$

Put n = 2 to find the second term.

$t_2=2(2)+3=7$

Put n = 3 to find the third term.

$t_3=2(3)+3=9$

Put n = 10 to find the tenth term.

$t_{10}=2(10)+3=23$

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

$S_=\dfrac{n}{2}(a+a_n)$

We have, n = 10, a = 5 and $a_n=23$

So,

$S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280$

So, the value of $S_{10}$ is equal to 280.

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iVinArrow [24]

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3 years ago

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padilas [110]

Answer:

Yes. No graph paper.

Step-by-step explanation:

Let's say the 3 points are A, B, C.

If A, B and C lie on one line then $m_{AB} = m_{BC} = m_{AC}$

$m_{AB} = \frac{y_{B}-y_{A} }{x_{B}-x_{A}} = \frac{2-6}{3-5} = \frac{-4}{-2} = 2\\m_{BC} = \frac{y_{C}-y_{B} }{x_{C}-x_{B}} = \frac{8-2}{6-3} = \frac{6}{3} = 2\\\\m_{AC} = \frac{y_{C}-y_{A} }{x_{C}-x_{A}} = \frac{8-6}{6-5} = \frac{2}{1} = 2\\\\$

Hence, they lie on one line.

You don't need to use a graph paper to prove it.

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Answer:

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Step-by-step explanation:

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