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vagabundo [1.1K]
4 years ago
13

Story Problem

Mathematics
2 answers:
jok3333 [9.3K]4 years ago
8 0

Answer:

245.10

Step-by-step explanation:

You have to multiply $6.45 by 38

Vlad [161]4 years ago
8 0

Answer:

245.10$

*DON'T FORGET MARK ME AS BRAINLIEST!

Step-by-step explanation:

multiply $6.45×38

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105 watermelon in 7 crates rate
Effectus [21]
Divide 105 by 7 to get 15
6 0
4 years ago
Read 2 more answers
Please Help Meh I dont Get this
LekaFEV [45]
The final answer is x = -19/6. The first step is to reduce the expression to
2/3 * 3(5-3x)= 29. This will make the equation much easier. The next step is to simplify by cancelling out the 3 in 2/3 with the 3 multiplying 5-3x so it leaves you with 2(5-3x)=29. Then you would remove the parenthesis by using the distributive property and simplifying 2(5-3x) to 10-6x= 29. Then subtract 10 from both sides, which leaves you with -6x = 19. Divide by -6 on both sides and you get x= -19/6. Hope this helps
4 0
3 years ago
In the diagram, ABCD is a part of a right angled triangle ODC. If /AB/= 6 cm,
Andreas93 [3]

Answer:

1) 13.3 cm

2) 48.3 cm

Step-by-step explanation:

1) Right angled triangle ODC and right angled triangle OAB are similar because AB//DC. The two triangles have the same proportion and are equiangular (having equal angles) but have different lengths.

Let OB = x, OC = OB + BC = x + 8

Therefore:

\frac{OC}{OB}=\frac{DC}{AB}  \\\frac{x+8}{x}=\frac{15}{6}\\15x=6(x+8)\\15x=6x+48\\15x-6x=48\\9x=48\\x=5.3\ cm

The height of triangle ODC = OC =  x + 8 = 5.3 + 8 = 13.3 cm

2) Using Pythagoras theorem:

OD² = OC² + DC²

OD² = 13.3² + 15²

OD² = 401.89

OD = √401.89 = 20 cm

2) perimeter of triangle ODC = OD + OC + DC = 20 + 13.3 + 15 =48.3 cm

3 0
3 years ago
La Michoacana bakery bakes 120 pieces
Katena32 [7]

Answer:

120

Step-by-step explanation:

8 0
3 years ago
How do you do this question?
mars1129 [50]

Answer:

I = ∫₀¹ eˣ dx

I = ∫₀¹ e⁻ˣ dx

Step-by-step explanation:

Trapezoidal rule will be an overestimate if the function is concave up.

We can determine this by looking at the graph, or by evaluating the second derivative.  If the second derivative is positive on the interval, the function is concave up.

f(x) = eˣ

f'(x) = eˣ

f"(x) = eˣ

On the interval [0, 1], f(x) is concave up.

f(x) = e⁻ˣ

f'(x) = -e⁻ˣ

f"(x) = e⁻ˣ

On the interval [0, 1], f(x) is concave up.

f(x) = √x = x^½

f'(x) = ½ x^(-½)

f"(x) = -¼ x^(-³/₂)

On the interval [0, 1], f(x) is concave down.

f(x) = sin x

f'(x) = cos x

f"(x) = -sin x

On the interval [0, 1], f(x) is concave down.

7 0
3 years ago
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