Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So






Rounding up
We need a sample size of 564.
X≤7
x>3
As a result, the answer will be
3 less than x and less than or equal 7. Hope it help!
she has $13.80 every hour because 842 divided by 40 plus 12 equals 61 so then and you cant round anymore.
Answer:
160 miles away
Step-by-step explanation:
I am BIG brain