Answer:
<h3>A production level that will minimize the average cost of making x items is x=5.</h3>
Step-by-step explanation:
Given that

is the cost of manufacturing x items
<h3>To find a production level that will minimize the average cost of making x items:</h3>
The average cost per item is 
Now we get 
<h3> f(x) is continuously differentiable for all x</h3>
Here x≥0 since it represents the number of items.,
Put x=0 in 
For x=0 the average cost becomes 13000


<h3>∴ f(0)=13000</h3><h3>To find Local extrema :</h3>
Differentiating f(x) with respect to x



<h3>∴ x=5 gives the minimum average cost .</h3><h3>At x=5 the average cost is </h3>


<h3>∴ f(5)=12825 which is smaller than for x=0 is 13000</h3><h3>∴ f(x) is decreasing between 0 and 5 and it is increasing after 5.</h3>
Answer:
<u>S2</u>
1. P is represented by -7
2. 1/2
Step-by-step explanation:
1. The P dot is right on the -7 mark, therefore, the number is -7
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2. There are 3 shaded out of 6, making it 3/6. Once you reduce 3/6, you would get 1/2
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Have a good day :)
I don't think you need to do anything special for this question. But do be careful how you read it.
Total number of instruments = 63
Number of woodwinds = 21
Number of non woodwinds = 63 - 21 = 42 non woodwinds.
What you have to be careful about is that this is not the answer.
It says how many more .... So now you have to do another subtraction.
Total number more = Number of non woodwinds - woodwinds.
Total number more = 42 - 21
Total number more = 21 <<<< Answer