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3 years ago

11

Help please Brainiest answer to whoever is first

1 answer:

Degger [83]3 years ago

6 0

Should be 1204.75? use this answer to check your work!

My work:
14 times 18 (since there’s two triangles) = 252
36 times 28 = 1008
6.5 times 8.5 = 55.25

(1008 + 252) - 55.25 = 1204.75

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The 80 eighth graders took a trip to Washington DC. The boys numbered 16 fewer than twice the number of girls. How many of the e

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32

Step-by-step explanation:

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3 years ago

Six and forty-two ten-thousandths as a decimal

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3 years ago

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4 years ago

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3 years ago

()) A rectangular piece of paper has a perimeter of 22 inches and an area of 28 square

Natasha2012 [34]

Given:

Perimeter of a rectangular paper = 22 inches.

Area of the rectangular paper = 28 square inches.

To find:

The dimensions of the rectangular paper.

Solution:

Let l be the length and w be the width of the rectangular paper.

Perimeter of a rectangle is:

$P=2(l+w)$

Perimeter of a rectangular paper is 22 inches.

$2(l+w)=22$

$l+w=\dfrac{22}{2}$

$l=11-w$ ...(i)

Area of a rectangle is:

$A=lw$

Area of the rectangular paper is 28 square inches.

$28=lw$

Using (i), we get

$28=(11-w)w$

$28=11w-w^2$

$w^2-11w+28=0$

Splitting the middle term, we get

$w^2-7w-4w+28=0$

$w(w-7)-4(w-7)=0$

$(w-7)(w-4)=0$

Using zero product property, we get

$(w-7)=0\text{ and }(w-4)=0$

$w=7\text{ and }w=4$

If $w=7$ , then by using (i)

$l=11-7$

$l=4$

If $w=4$ , then by using (i)

$l=11-4$

$l=7$

Therefore, the dimensions of the paper are either $7\times 4$ or $4\times 7$ .

5 0

3 years ago