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3 years ago

How many groups of 8 are in 70

Mathematics

2 answers:

jenyasd209 [6]3 years ago

8 0

There are 8 groups of 8 in 70 with the remainder of 6. Hope this helped!<span>
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Feliz [49]3 years ago

3 0

There are 8 groups of 8 in 70

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A 12,000-lb killer whale might eat as much as 14,000 lb of fish per month (assume a 30-day month). If the average weight of a ce

brilliants [131]

Answer:

2196 fish

Step-by-step explanation:

Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb

Weight of the fish that killer whale might eat in a day = $\frac{14000}{30} = \frac{1400}{3}$ lb.

Average weight of the fish that killer whale eats = 3.4 oz

Since,

1 pound(lb) = 16 ounces(oz)

So,

Weight of the fish that killer whale might eat in a day in ounces(oz) = $\frac{1400}{3} \times 16=\frac{22400}{3}$ oz

Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.

So, the number of fish that killer whale would eat = $\frac{22400}{3} \div 3.4 = 2196$ fish

Thus, the killer whale needs to eat 2196 fish.

8 0

4 years ago

A survey was conducted that asked 1011 people how many books they had read in the past year. results indicated that x overbarequ

Tcecarenko [31]

Since we do not know the population standard deviation, we will use the t-distribution to construct the 90% confidence interval of the mean number of books people read. The value of $t_{\frac{\alpha }{2}}$ with 1010 degrees of freedom and with alpha equals to 0.10 is 1.64

First, we need to solve for the margin of error, E.
$E=t_{\frac{\alpha }{2}}\cdot \frac{s}{\sqrt{n}}=1.64\cdot \frac{16.6}{\sqrt{1011}}=0.86$

The lower bound of the confidence interval is
$LB=\overline{x}-E=14.8-0.86=13.94$

The upper bound of the confidence interval is
$LB=\overline{x}+E=14.8+0.86=15.66$

Therefore, the 90% confidence interval is (13.94, 15.66).

We are 90% confident that the interval from 13.94 books to 15.66 books does contain the true value of the population mean number of books people read.

4 0

4 years ago

I can’t understand this, I’m kinda du.mb

Natalka [10]

Answer:

sheshhhhhhhhhhhhhhhhhh

Step-by-step explanation:

seeeeeeeeeeeeeeeeeeeeeeeeeeeshhhhhhhh

4 0

3 years ago

Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t

gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

4 0

3 years ago

Help me with questions 3 & 4

ASHA 777 [7]

3. -4x - 6

-3(x + 2) - x → ( distribute bracket by - 3)

= - 3x - 6 -x → (collect like terms)

=( - 3x - x) - 6 = - 4x - 6

4. A has the smallest value

A =( 2 - 3 ) = -1

B = 2 × 3 = 6

C = 2 + 3 = 5

D = $\frac{2}{3}$

A is negative while the others are all positive.

Thus A is the smallest value expression

6 0

3 years ago