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melamori03 [73]
4 years ago
15

What's 2/5 in decimal

Mathematics
1 answer:
Vaselesa [24]4 years ago
5 0
2/5 = (2x2)/(5x2) = 4/10 = 0.4
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(5x^5) - (80x^3)<br> factoring
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Answer:

Factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

Step-by-step explanation:

We need to factor the term (5x^5) - (80x^3)

First we can see that 5x^3 is common in both terms

So, taking 5x^3 common:

(5x^5) - (80x^3)\\=5x^3(x^2-16)

We can write x^2-16 as (x)^2-(4)^2

=5x^3((x)^2-(4)^2)

Now we can solve (x)^2-(4)^2 using the formula: a^2-b^2=(a+b)(a-b)

We can write:

=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)

So, factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

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Rationalize <br>√3 ÷ √7-√5​
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Multiply by the opposite sign the denominator. In the denominator we have the difference of squares.

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