A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which expression would det

Question

4 years ago

14

ermine the probability that both digits are even?

2 answers:

sweet-ann [11.9K] · Answer 1 · 2021-12-23T00:34:13+03:00

5 0

The answer is the first choice.

P(both even) = (4P1)(3P1) / 9P2

notka56 [123] · Answer 2 · 2021-12-23T02:11:40+03:00

5 0

The correct answer is:

A. P(both even) = $\frac{(_{4}P_{1})(_{3}P_{1})}{_{9}P_{2}}$

The expression would determine the probability that both digits are even.

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