Question

A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which expression would determine the probability that both digits are even?

Answer 1

The answer is the first choice.

P(both even) = (4P1)(3P1) / 9P2

Answer 2

The correct answer is:

A. P(both even) = $\frac{(_{4}P_{1})(_{3}P_{1})}{_{9}P_{2}}$

The expression would determine the probability that both digits are even.

$|Huntrw6|$