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3 years ago

Expand and simplify: (2x + 5y) (3x − 2y)

Mathematics

1 answer:

mario62 [17]3 years ago

4 0

Answer:

Expand:5x+3y

Simplify:6x^2+11xy-10y^2

Step-by-step explanation:

2x(3x-2y)+5y(3x-2y)

6x^2-4xy+15xy-10y^2

6x^2+11xy-10y^2

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Alan just got a Fall job. The equation P = 12.50h represents the salary P (in dollars) he will earn when he works h hours. How m

balandron [24]

Given:

Alan salary P (in dollars) when he works h hours is represented by the equation

$P=12.50h$

To find:

The earning per hour.

Solution:

We have,

$P=12.50h$

Here, P is total salary and h is number of hours he works.

$\text{Earning per hour}= \dfrac{\text{Total salary}}{\text{Number of hours}}$

$\text{Earning per hour}= \dfrac{12.50h}{h}$

$\text{Earning per hour}=12.50$

Therefore, the earning per hour is $12.50.

8 0

3 years ago

he has 1/6 of the pie left over. if he shares it with three friends, how much of original pie will each of the four people get?

mario62 [17]

Sharing with three friends:
1/24 of original pie
Sharing with little brother:
1/12 of original pie

3 0

2 years ago

Read 2 more answers

Which number is between 3.22 and 3.36? <br> A. 3.2<br> B. 3.93<br> C. 3.37

siniylev [52]

Answer:

Step-by-step explanation:

5 0

3 years ago

Find the length of side x to the nearest tenth

navik [9.2K]

Answer:

x = 2 sqrt(3)/3

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 60 = 1 /x

x sin 60 =1

x = 1 /sin 60

x = 1 / sqrt(3)/2

x = 2 sqrt(3)/3

3 0

2 years ago

Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .