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3 years ago

Use the distributive property to simplify the expression 6(s-9

Mathematics

1 answer:

Natalija [7]3 years ago

7 0

You have to multiply the 6 by both s and -9

So you will get 6s - 54 which is the answer

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Is this correct or need more? but still need help

lana [24]

8 ft= ___ inches
1 ft= 12 inches
8 ft= 12 x 8 inches
8 ft=96 inches
She has 96 inches, but she needs 100 inches. So she needs 4 more inches of lumber.

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3 years ago

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A class was conducting a series of probability experiments.

leva [86]

I believe the answer would be B, since both situations give you 6 chances at drawing/rolling the right number/marble.

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2 years ago

one evening, 2/3 of the students in Rick's class watched television. of this students, 3/8 watched a reality show. Of the studen

Dimas [21]

Answer:

0.0625 of the students recorded the show.

Step-by-step explanation:

2/3×3/8×1/4= the fraction of people who watched and recorded the show (0.0625)

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3 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

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1 year ago

HELP HURRY Find the distance from A to C. 12 74 6

Rainbow [258]

Answer:

It's B :)

Step-by-step explanation:

5 0

3 years ago

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