Help me on 12 and 13 please
1 answer:
Answer:
12. h=3
13. h=-3
Step-by-step explanation:
12. Recall that is a horizontal shift since h is being applied within the operation to the input. This means that h will slide the function left or right. Since the function f has a point at (1,-2) and g has the same point at (4,-2) then the function has moved 3 units 1+3=4 to the right. h=3.
13. Once again, h is a horizontal shift meaning the graphs has moved left or right only. Looking at g it has a point at (-2,2) while f has the same point at (1,2). So the graph f has moved to the left 3 units. This is h=-3 since 1+-3 = -2.
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The option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.
<h3>What is the similarity law for triangles?</h3>It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have given two triangles:
Triangle RST and Triangle VUT
AS we can see Line segment RS and UV are parallel.
Which is crossed by a transversal RV.
The angle SRV = Angle RVU
Thus, the option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.
Learn more about the similarity of triangles here:
#SPJ1
Answer:
5y = x + 11
Step-by-step explanation:
Given parameters:
Equation of the line ;
y = -5x + 1
Coordinates = (2, -1)
Find the equation of a line perpendicular;
Solution:
A line perpendicular to y = -5x + 1 will have slope that is a negative inverse of the given one.
Equation of a straight line is expressed as;
y = mx + c
y and x are the coordinates
m is the slope
c is the y-intercept
So, the slope of the new line perpendicular is ;
Now let us find the y-intercept of the new line;
x = -1 and y = 2
2 = x (-1) + c
c = 2 + =
The equation of the new line is;
y = x +
or multiply through by 5;
5y = x + 11