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vesna_86 [32]
3 years ago
10

Y=f(x)=-5x find f(x) when x=3

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

Answer:


Step-by-step explanation:

y=f(x)=-5x

since x=3 just replace x with 3

y=f(x)=-5(3)

y=f(x)=-15

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Is (2,5) a solution of y=3x-10?
Lynna [10]
To see if (2,5) is a solution of the line y = 3x - 10, you need to plug in the coordinate values for x and y. This gets you 5 = 3(2) - 10. Evaluating the right side gives 5 ≠ -4, which is not a true statement. This means that the answer to your problem is no, (2,5) is not a solution of y = 3x - 10. Hope this helps and have a nice day!
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Divide this for me someone plssss
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Answer:

  It is the 3rd one

Step-by-step explanation:

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What is a commutative property of multiplication?
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Find the limit, if it exists. (if an answer does not exist, enter dne.) lim (x, y) → (0, 0) x4 − 20y2 x2 + 10y2
Firdavs [7]
Traveling along the x-axis, we have

\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{x\to0}\frac{x^4}{x^2}=\lim_{x\to0}x^2=0

On the other hand, along the y-axis we get

\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{y\to0}\frac{-20y^2}{10y^2}=\lim_{y\to0}(-2)=-2

Therefore the limit doesn't exist.
5 0
3 years ago
Question 1 of 4
Aliun [14]

OB. The digits in the millions period are 41, the digits in the thousands period are 000, and the digits in the ones period are 138.

The digits of a number can be classified into into 3 groups and each such group is called a period.

Here, we are give a number 41,000,138.

In this number, the million period consists of

ten millions - 4

and millions - 1

Hence the digits in the million periods are 41

The thousand period consists of all zeroes, hence the digits in thousand periods are 000.

The ones period contains-

hundreds - 1

tens - 3

and ones - 8

Thus, the digits in the ones period are 138

Hence, option B is the correct answer.

Learn more about place value here-

brainly.com/question/12386995

#SPJ9

6 0
2 years ago
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