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yulyashka [42]
3 years ago
13

Find the values for A and B that would make the equality true -5(3x^2+5x+b)=ax^2-25x+45

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
8 0

Answer:

a = - 15 and b = - 9

Step-by-step explanation:

distribute the left side

- 15x² - 25x - 5b

For - 15x² - 25x - 5b = ax² - 25x + 45

Then the coefficients of like terms must be equal, hence

comparing coefficients of x² term ⇒ a = - 15

comparing constant term ⇒ - 5b = 45 ⇒ b = - 9



kondor19780726 [428]3 years ago
8 0

Answer: a = -15,   b = -9

<u>Step-by-step explanation:</u>

-5(3x² + 5x + b) = ax² - 25x + 45

-15x² - 25x - 5b = ax² - 25x + 45       <em>distributed -5 on left side</em>

Notice that the middle terms (-25x) are equal, so the the remaining terms will also be equal.

-15x² = ax²  ⇒  -15 = a

 -5b = 45   ⇒   b = -9

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We know that
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