We have the next information
x= the shortest side measure
y= the second side measure
y=x+100
z= the third side measures
z=x+700
We know also that the perimeter is 2900 ft
Therefore the equation for the perimeter of the triangle will be
we sum like terms
then we isolate the x
therefore
x=700ft
y=700+100=800ft
z=700+700=1400ft
The lengths of the sides of the lote are 700 ,800, and 1400 ft,
When you simplify the expression 1/1+cot^2x the final product is C. sin^2 (x).
Hope this helps!
Answer:
The answer to your question is the second option 
Step-by-step explanation:
Expression
![[\frac{(x^{2}y^{3})^{-2}}{(x^{6}y^{3}z)^{2}}]^{3}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%28x%5E%7B2%7Dy%5E%7B3%7D%29%5E%7B-2%7D%7D%7B%28x%5E%7B6%7Dy%5E%7B3%7Dz%29%5E%7B2%7D%7D%5D%5E%7B3%7D)
Process
1.- Divide the fraction in numerator and denominator
a) Numerator
[(x²y³)⁻²]³ = (x⁻⁴y⁻⁶)³ = x⁻¹²y⁻¹⁸
b) Denominator
[(x⁶y³z)²]²= (x¹²y⁶z²)³ = x³⁶y¹⁸z⁶
2.- Simplify like terms
a) x⁻¹²x⁻³⁶ = x⁻⁴⁸
b) y⁻¹⁸y⁻¹⁸= y⁻³⁶
c) z⁻⁶
3.- Write the fraction
Answer:
4/675
Step-by-step explanation:
There can be 90 two-digit numbers ranging from 10 to 99. There will be
90 x 90= 8100 possibilities of randomly selecting and combining 2 entire two-digit numbers, if we find ax b to be distinct from bx a. When 10 is first chosen, there may be 9 two-digit numbers that could be combined within the required range for a product When 11 is chosen first, then the second two-digit number has 9 possibilities. 12 has seven options; 13 has six options; 14 has five options; 15 has four options; 16 has three options; 17 has two options; 18 has 2 options; and 19 has one option. It provides us 48 total choices so the likelihood that the combination of two randomly chosen two-digit whole numbers is one of theses these possibilities is thus 48/8100 = 4/675.
