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Brums [2.3K]
3 years ago
12

3. company pays a greater annual salary? Show your Company A offers a semimonthly salary of $2432, and Company B offers a biweek

ly salary of $2390. Which work.
Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0
Company A offer
2,432×24(semimonthly)
=58,368 per year

Company B offer
2,390×26 (biweekly)
=62,140 per year

So company B pays a greater annual salary

Hope it helps!
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Please help ASAP <br> Find the slope of the line graphed below.
irina1246 [14]

Answer:

3/4

Step-by-step explanation:

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8 0
2 years ago
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maze going to the lake to visit some friends at the lake is 60 miles away and Renee is driving 40 mph the entire time how long w
mojhsa [17]

Answer:

it will take her an hour and 25 minutes roughly

Step-by-step explanation:

7 0
3 years ago
A figure in the first quadrant is rotated 180° counterclockwise about the origin. In which quadrant will the rotated figure appe
Leni [432]
It will be in the 3rd quadrant.
5 0
3 years ago
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A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
Weight/Calories per Day 1000 to 1500 cal. 1500 to 2000 cal. 2000 to 2500 cal. Total
Lady bird [3.3K]
<h2>Answer:</h2>

Option: D is the correct answer.

The probability is: 0.50

<h2>Step-by-step explanation:</h2>

Weight/Calories  1000-1500   1500-2000  2000-2500   Total

    120 lb.                 90               80                   10               180

    145 lb.                 35               143                  25              203

    165 lb.                  15                27                  75               117

    Total                140               250                110             500

We are asked to find the probability that a person consumes 1500-2000 calories in a day.

Total number of people who were surveyed=500

Total number of people who consume 1500-2000 calories in a day are:250

              Hence, Probability is:

                250/500=1/2=0.50

6 0
3 years ago
Read 2 more answers
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