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ahrayia [7]
3 years ago
10

What is 6:12 in simplest form? A.2 B.21 C. 12 D. 12.6

Mathematics
2 answers:
vovikov84 [41]3 years ago
8 0

Answer: 1:2 or 1/2

Step-by-step explanation:

6:12

Step 1: find a common divisible value, in this case, it is 6

Step2: divide through 6

1:2 or 1/2

Mekhanik [1.2K]3 years ago
4 0

Answer:

It’s B

Step-by-step explanation:

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For a line to be parallel it has to have the same slope as the original line. so the slope is 1/2 
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8 0
3 years ago
You measure 22 textbooks' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 5.
lara31 [8.8K]

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the true population mean textbook weight.

Number of sample, n = 22

Mean, u = 64 ounces

Standard deviation, s = 5.1 ounces

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

It becomes

64 ± 1.645 × 5.1/√22

= 64 ± 1.645 × 1.087

= 64 ± 1.788

The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces

The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces

Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces

3 0
3 years ago
find the number of terms in an AP given that its first and last terms are 13 and - 23 respectively and that its common differenc
Leokris [45]

Answer:

<u>There are 17 terms in the sequence</u>

Step-by-step explanation:

<u>Arithmetic Sequence </u>

An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:

a_n=a_1+(n-1)r

Where an is the nth term, a1 is the first term, and r is the common difference.

In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:

\displaystyle n=1+\frac{a_n-a_1}{r}

We need to express r as an improper or proper fraction:

\displaystyle r=-2\frac{1}{4}=-2-\frac{1}{4}=-\frac{9}{4}

Substituting:

\displaystyle n=1+\frac{-23-13}{-\frac{9}{4}}

\displaystyle n=1+\frac{-36}{-\frac{9}{4}}

\displaystyle n=1+36*\frac{4}{9}=17

n=17

There are 17 terms in the sequence

5 0
3 years ago
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