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3 years ago

20 points...Can someone help me create a real world problem with an equation to solve it? For my algebra class.

1 answer:

7 0

Bob's motorboat rents a motorboat for $52 an hour plus an extra $6. If Jenna rents a motorboat for 6 hours how much will it cost her?

Equation: 52x+6=y

X=6 so 52•6+6= 318

So she would pay $318

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Rounded what is 489291 rounded to the nearest hundred

Mrac [35]

The answer is 489,300.

Work:

We go to the tenth's place, which is 9. Since 9 is higher than 5, we need to round the hundredth's place to 3.

8 0

2 years ago

Read 2 more answers

An exponential function f(x) = ab^xpasses through the points (0, 2) and (3, 54). What are the values of a and

Vsevolod [243]

Answers:

a = 2

b = 3

=======================================================

Explanation:

Plug in x = 0 and y = 2 to find that

y = a*b^x

2 = a*b^0

2 = a*1

2 = a

a = 2

Then plug in x = 3 and y = 54 to determine the value of b

y = a*b^x

y = 2*b^x

54 = 2*b^3

2b^3 = 54

b^3 = 54/2

b^3 = 27

b = (27)^(1/3)

b = 3

So we have y = a*b^x update to y = 2*3^x

7 0

2 years ago

An aluminum can is a right cylinder. Find the amount of paper needed for the can's label and the total amount of aluminum needed

statuscvo [17]

Answer:

you did not specify the diamiter of the can please add another question and i will help

Step-by-step explanation:

it is imposible to answer right now

6 0

2 years ago

You and your friend are painting the walls in your apartment. You estimate

Novay_Z [31]

Answer:

Honestly I dont know man, Im pretty sure you already found thee answer already since this was in April

Step-by-step explanation:

3 0

3 years ago

Plz need help on 1. 2. and 3 plz help and dont answer if you dont know it plz

sesenic [268]

Answer:

1) 32 $m^{6}$ $n^{14}$

2) 3 $j^{4}$ $k^{8}$

3) 135 $a^{11}$ $b^{16}$

Step-by-step explanation:

to know: when multiplying terms with same base and exponents, multiply the bases and add the exponents

to know: when dividing terms with same base and exponents, divide the bases and subtract the exponents

to know: whenever exponents are contained within a set of parentheses and separated by another set of parentheses, multiply the exponents

1) ( $4^{4}$ · $m^{12}$ · $n^{20}$ ) ÷ 2³ $m^{6}$ $n^{6}$ = 3 $j^{4}$ $k^{8}$

2) (15 $j^{5}$ $k^{2}$ · 25j² $k^{9}$ ) ÷ 5³j³k³ = (375 $j^{7}$ $k^{11}$ ) ÷ 125j³k³ = 3 $j^{4}$ $k^{8}$

3) (5 · 3³) $a^{11}$ $b^{16}$ = 135 $a^{11}$ $b^{16}$

5 0

2 years ago