Steps to finding the inverse:
1. Replace f(x) with y.
2. Swap x and y.
3. Solve the equation for y.
f(x) = 2x - 10
1. y = 2x - 10
2. x = 2y - 10
3. Add 10 to both sides
x + 10 = 2y
Divide both sides by 2
(x + 10)/2 = y
y = (x + 10)/2
f^-1(x) = (x + 10)/2
Answer:
I think it is 35.
Step-by-step explanation:
Because I think what you do is subtract every number by each other for example 9 minus 10, 11 minus 15, 13 minus 20 so on and so on and then when you get all the answers add them all together and that's your answer. But I don't know so if it is wrong dont get mad at me because I'm only in 6th grade.
Exact numbers are numbers are exact (and therefore have an unlimited number of significant figures)
<h3>What are exact numbers?</h3>
Exact numbers can be defined as numbers known with complete certainty.
These numbers have zero uncertainty and have infinite values.
Some examples of exact numbers are:
- counted numbers of objects or certain unit conversions such as 3 feet in 1 yard, exactly 12 eggs in a dozen
We can see that exact numbers have infinite values and thus have unlimited number of significant figures.
Thus, exact numbers are numbers are exact (and therefore have an unlimited number of significant figures)
Learn more about number systems here:
brainly.com/question/17200227
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I find it easier to start from scratch and write out the equations, then compare them with the given equations.
Let m and j represent the ages of the two boys. Then m-5=(2/3)(j-5)
Also, in ten years: m+10 = (5/6)j.
Let's solve this system: Mult the first eqn by 3 to remove the fraction:
3(m-5) = 2(j-5), or 3m - 15 = 2j -10. Next, mult. the 2nd eqn by 6 to remove the fraction: 6m+60 = 5j.
Our two equations are (at this point) 3 m - 15 = 2j - 10 and
6m +60 = 5j
Let's mult. the first equation by -2, so as to obtain the coefficient -6 for m:
-6m + 30 = -4j + 10
6m + 60 = 5j
---------------------------
90 = j + 10, so j = 80 (wow!)
Let's now find m: 6m + 60 = 5(80), or 6m = 400+60 = 460
Then m = 76 2/3.
We must check our solution (m = 76 2/3, j = 80):
Let's subst. these values into m-5=(2/3)(j-5)
Does 76 2/3 - 5 = (2/3)(80) - 10/3?
Does 76 2/3 - 15/3 = 160/3 - 10/3?
Does 76 - 15 = 160 - 10 No. So something's wrong here.
Going back to the problem statement:
<span>x-5=2/3(y-5) and x+10=5/6(y+10) seems correct!
Mike's age 5 years ago was x-5, and james' age 5 years ago was y-5. The multiplier (2/3) is also correct.
Mikes age 10 years from now will be x+10, and james' y+10.
The first answer set is the correct one.</span>
Hi!
We will subtract the budget with the sum that was actually spent, like this:
8,000,000 - 12,000,000 = -4,000,000
The city's deficit is -4,000,000
Hope this helps!
