3 years ago

Exponents: Can me help me? This is the one, I just can't get.

Mathematics

1 answer:

aliina [53]3 years ago

4 0

Answer:

Step-by-step explanation:

x^y * x^-y

When the bases are the same, we add the exponents when multiplying

x^(y-y)

x^0

Anything to the zero power is 1 (except 0)

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$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
4x^2-9=0\implies 2^2x^2-3^2=0\implies (2x)^2-3^2=0
\\\\\\\
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2x=3\\
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