Question

Find the disciminant of the quadratic equation: le="4k^2+8k+4=0" alt="4k^2+8k+4=0" align="absmiddle" class="latex-formula">

Answer 1

here

• a=4
• b=8
• c=4

Discriminant

• D=b²-4ac
• D=8²-4(4)(4)
• D=64-4³
• D=64-64
• D=0

Answer 2

Answer:

0 (zero)

Step-by-step explanation:

Discriminant

$b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0$

Given equation:  $4k^2+8k+4=0$

Therefore:

• a = 4
• b = 8
• c = 4

Substitute these values into the discriminant and solve:

$\begin{aligned}\implies b^2-4ac & = 8^2-4(4)(4)\\& = 64 - 4(16)\\& = 64 - 64\\& = 0\end{aligned}$

Therefore, the discriminant of the given quadratic equation is zero.

This implies that the graph of the equation has one real root.