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3 years ago

How do i simplify 45/99 into a fraction

2 answers:

7 0

45/99= 5/11

what you do to get this lesson is find the LCM ( least common denominator) after you find that you can divide it by the top and the bottom and then you'll get your answer.

Travka [436]3 years ago

4 0

Put it in a decimal then divide

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Rectangle ABCD has vertices A(–6, –2), B(–3, –2),

Tatiana [17]

Answer:

A. T–4, 3(x, y)

Step-by-step explanation:

We are given that the transformation changes the rectangle ABCD to the rectangle A'B'C'D'.

The changes in the co-ordinates are given by,

A = (-6,-2) = (-6,-2) + (-4,3) = (-10,1)

B = (-3,-2) = (-3,-2) + (-4,3) = (-7,-1)

C = (-3,-6) = (-3,-6) + (-4,3) = (-7,-3)

D = (-6,-6) = (-6,-6) + (-4,3) = (-10,-3)

So, we see that the rectangle ABCD is transformed by the co-ordinates (-4,3).

That is, it is translated 4 units to the left and 3 units upwards.

Thus, option A is correct.

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3 years ago

All whole numbers are integers, and all integers are also whole numbers.

igor_vitrenko [27]

This statement is True I made sure

8 0

3 years ago

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PLEASE HELP ME If this rectangle is dilated using a scale factor of One-half through point B, what is the result? Point B is the

elixir [45]

Answer:

It is B just took the unit quiz

4 0

2 years ago

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Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o

wel

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is $x = 274 \ unites$

Step-by-step explanation:

From the question we are told that

The length of the vertical length is $x$

The length of the base leg is L = 330 + d units

The length of the bisecting line segment is h

The base angle is $\theta = 28^o$

The angle between d and line segment is $\theta_1 = 56^o$

For the first angle

$Tan \theta_1 = \frac{x}{d}$

=> $d = \frac{x}{Tan \theta _1}$

For the whole big triangle

$Tan \theta = \frac{x}{330 + d}$

=> $d = \frac{x}{Tan \theta } -330$

So equating the both d

$\frac{x}{Tan \theta _1} = \frac{x}{Tan \theta } -330$

Substitute values

$\frac{x}{Tan (56)} = \frac{x}{Tan (28) } -330$

$0.6745 x = 1.880x -330$

$1.20549 x = 330$

$x = 274 \ unites$

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3 years ago

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Answer:

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2 days:

3 days:

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3 years ago

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