Answer:
i wish i could help but its kind of over a minute but the answer is C
Answer:
Step-by-step explanation:
The initial height of a Japanese maple sapling is 14 inches.
The tree is expected to grow 2.5 inches each month. This increase in height is linear, thus it is in arithmetic progression.
The expression for arithmetic progression is
Tn = a + (n-1)d
Where a = the first term of the series
d = common difference
Tn is the nth term of the series
n = the number of terms.
From the information given
a = 14 inches because it is the initial height of the tree
d = 2.5 because it is the difference in height between 2 consecutive months
n = m( number of months)
Tn = f(m)
function models the relationship between the height of the tree f(m) and the number of m months of growth will be
f(m) = 14 + 2.5(m-1)
Answer:
hehjzjxjxjdjjdhdhdhdhjdjdjhdhdhdhdjdjjdjsjs B is correct
Uhhhh I don't think that the correct answer.
First, find the gradient of the line segment.
Gradient = Rise/Run = (2-6)/(2-5) = 4/3.
Since the other line segment is parallel to this line segment, their gradients are the same.
That means (-2+4)/(x-5) = 4/3.
2/(x-5) = 4/3
It is obvious x = 6.5
