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djverab [1.8K]
4 years ago
9

Write an expression to show the difference of 3 and p.

Mathematics
2 answers:
Digiron [165]4 years ago
5 0

Answer:

3 - p

Step-by-step explanation:

"the difference of 3 and p" is represented symbolically by 3 - p.

ra1l [238]4 years ago
4 0

Answer:

3 - p

Step-by-step explanation:

Difference means subtraction

And means together

So the question is asking what an expression would look like when subtracting 3 and p

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The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int
geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given:  The average (arithmetic mean) of five different positive integers is 30.

To find:  What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five  positive integer

                   is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

                   \frac{A+B+C+D+E}{5} =30.

On multiplying both side by 5.

                       A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

  Then :  1 +2+3+4+E =150

On simplification  10+E =150

On subtraction both side by 10 we get

                      E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.


6 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
2 6 unit squares each have of their area shaded. 3 What is the total area that is shaded? square units​
Kobotan [32]

Answer:

6

Step-by-step explanation:

The area of each of the squares is 3. There's 2 so it's 6.

4 0
3 years ago
A company pays a bonus to four employees A, B, C, and D. A gets four times as much as B. B gets 50% of the amount paid to C. C a
Tomtit [17]

Answer:

A = 800, B = 200, C = 400 Andy D = 400

Step-by-step explanation:

5 0
3 years ago
Sample Response: You would graph the equation f(x) = –x + 3 for input values less than 2. There would be an open circle at the p
fgiga [73]

Answer:

Step-by-step explanation:

What did you include in your response? Check all that apply.

There would be an open circle at (2, 1).  <u>Yes</u>

There would be a closed circle at (2, 3).  <u>Yes</u>

There would be an open circle at (4, 3).  <u>Yes</u>

There would be a closed circle at (4, −4).  <u>Yes</u>

Endpoints that are not included in the domain of a particular piece of a function are represented by an open circle.  <u>Yes</u>

7 0
3 years ago
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