Answer:
n+(n+2)+20=4n
Step-by-step explanation:
Let the smaller integer be n,
the bigger odd integer will be n+2.
n+(n+2)+20=4n
2n+22=4n
2n=22
n=11
I think the answer is 7.725 so sorry if I’m wrong but see if that answer is correct
Definitely the question is incomplete
Using for loop in java to print positive integers ,let say first 50 integers
So the loop is:
int i ;
for( i= 0; i<= 50; i++ ) {
print (i);
}
The looping will going to start from the 1 and stop to 50
Here is a diagram:
In the future I would recommend Desmos Graphing Calculator