WILL GIVE BRAINLIEST
1 answer:
All you have to do is plug in the given values into the given equation and evaluate.
The expression is,
But we have to analyze the problem carefully. This is a natural phenomenon that can be modelled by a decay function. The reason is that, after every hour we expect the medicine in the blood to keep reducing.
Therefore we use the decay function rather. This is given by,
where,
and
On substitution, we obtain;
Now, we take our calculators and look for the constant
,then type e raised to exponent of -1.4. If you are using a scientific or programmable calculator you will find this constant as a secondary function. Remember it is the base of the Natural logarithm.
If everything goes well, you should obtain;
This implies that,
Therefore after 10 hours 24.66 mg of the medicine will still remain in the system.
The expression is,
But we have to analyze the problem carefully. This is a natural phenomenon that can be modelled by a decay function. The reason is that, after every hour we expect the medicine in the blood to keep reducing.
Therefore we use the decay function rather. This is given by,
where,
and
On substitution, we obtain;
Now, we take our calculators and look for the constant
,then type e raised to exponent of -1.4. If you are using a scientific or programmable calculator you will find this constant as a secondary function. Remember it is the base of the Natural logarithm.
If everything goes well, you should obtain;
This implies that,
Therefore after 10 hours 24.66 mg of the medicine will still remain in the system.
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Answer:
See below
Step-by-step explanation:
(a) Field lines
A negatively charged particle has an electric field associated with it.
The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.
Opposite charges attract, so the field lines point toward the centre of the particle.
For an isolated negative particle, the field lines would look like those in Figure 1 below.
If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.
A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.
We can make a similar statement about appositive charge approaching from the left.
Thus, there are few field lines in the region between the two particles.
(b) Coulomb's Law
The formula for Coulomb's law is
F = (kq₁q₂)/r²
It shows that the force varies inversely as the square of the distance between the charges.
Thus, the force between the charges decreases rapidly as they move further apart.
Answer:
The numbers are 9, 19 and 76.
Step-by-step explanation:
Let's take the second number and make it a variable, like x. Now let's find all the other numbers in terms of x.
The first number in terms of x:
The second number in terms of x:
If we add them all up, these 3 numbers in terms of x must be equal to 104, so:
Now that we know the second number, we can find the other numbers since we already figured out their values in terms of x:
The first number is 9, second number 19 and the third number 76.