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3 years ago

Angle 1 measure 75 degree what is its complement

1 answer:

3 0

I think it’s 76 because I added it that’s a way i solved it but you can also multiple it by 1 and it will give the the same answer

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What is one thousand minus seven?

rodikova [14]

The answer for one thousand minus seven is 993

4 0

4 years ago

Determine the value of a + b in the system of equations below. 5a + 4b = 22 7a-b= 11

dexar [7]

Answer:

We have a + b as;

2 + 3 = 5

Step-by-step explanation:

Here, we want go get the value of a and b

from the second equation, we can get an expression for b

We have this as;

7a - b = 11

Thus,

b = 7a - 11

Now, from here, we can substitute the value of b into the first equation

We have this as;

5a + 4(7a - 11) = 22

5a + 28a -44 = 22

33a = 22 + 44

33a = 66

a = 66/33

a = 2

Recall;

b = 7a - 11

substituting the value of a from above;

b = 7(2) - 11

b = 14 - 11

b = 3

6 0

3 years ago

-½(x + 1¼) = - 3 + ¼x Solve for x

crimeas [40]

Answer:

x = (23 + √ 497 / 8) , (23 − √ 497 /8)

x=5.66168710

Step-by-step explanation:

im too lazy. use math-way

6 0

3 years ago

A certain new type of business succeeds 60% of the time. Suppose that 3 such businesses open (where they do not compete with eac

ella [17]

Answer:

0.216

Step-by-step explanation:

Given that a certain new type of business succeeds 60% of the time.

3 such businesses are tested for success.

Since these three businesses open (where they do not compete with each other, so it is reasonable to believe that their relative successes would be independent). we can say X no of successful businesses is Binomial

with p = 0.6 and n =3

Required probability

=The probability that all 3 businesses succeed is:

= $P(X=3)\\= 0.6^3\\= 0.216$

8 0

3 years ago

Rod is saving Php2000 in a bank at the end of each month which gives an interest of 1% compounded monthly.How much is the saving

agasfer [191]

Answer:

Php2040.38

Step-by-step explanation:

Given

$P = 2000$ --- Principal

$r = 1\%$ --- Rate

$t = 2\ years$ --- Time

$n = 12$ --- monthly

Required

Determine the amount at the end of two years

This is calculated as:

$A = P(1 + \frac{r}{n})^{nt}$

So, we have:

$A = 2000(1 + \frac{1\%}{12})^{12*2}$

$A = 2000(1 + \frac{1}{100*12})^{24}$

$A = 2000(1 + \frac{1}{1200})^{24}$

$A = 2000(\frac{1200+1}{1200})^{24}$

$A = 2000(\frac{1201}{1200})^{24}$

$A = 2000*1.02019$

$A = 2040.38$

Hence, the final amount is: Php2040.38

7 0

3 years ago