Question

A goblet contains 2 red marbles, 6 green marbles, and 4 blue marbles.

Answer 1

Answer:

P(first marble will be green and the second will be green as well)= 5/22

Step-by-step explanation:

A goblet contains 2 red marbles, 6 green marbles, and 4 blue marbles.

Total number of marbles= 2+6+4

                                        =12

P(first marble is green)=no. of green marbles/total number of marbles

                                  =  6/12

                               = 1/2

P(second marble is green and we didn't put the first marble back)

=no. of green marbles left/total marbles left

= 5/11

Hence, P(first marble will be green and the second will be green as well)

       =$\dfrac{1}{2}\times \dfrac{5}{11}$

      = 5/22