When the rectangle ABCD is reflected across line EF, the image is DCBA. How do you
2 answers:
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Answer:
The graph of the function is negative on (3, ∞)
Step-by-step explanation:
The function starts negative at the left side of the graph, crosses the x-axis at x = -5, touches the x-axis at x = 1, again crosses into negative values at x = 3.
The function is positive on the open intervals (-5, 1) and (1, 3). It is negative on the open intervals (-∞, -5) and (3, ∞). The latter description matches the last answer choice:
the graph of the function is negative on (3, ∞).
Answer:
can be written as the single logarithm:
Step-by-step explanation:
Start by using in both terms of the expression the property of logarithm of a power that states:
so we recognize that the factor that multiplies each logarithmic expression, can be understood as the power of the argument of the function logarithm:
Then we use the property of logarithm of a product which states that:
So now we recognize the expression:
as the logarithm of the product:
which is finally a single logarithm as requested.