The large hose fills 1 pool in 9 hours written as 1/9
The small hose fills 1 pool in 18 hours, written as 1/18
Now you have 1/9 + 1/18 = 1/x ( x is the unknown time for both hoses).
rewrite 1/9 with a common denominator as 1/18:
1/9 = 2/18
Now you have 2/18 + 1/18 = 1/x
Add the left side:
2/18 + 1/18 = 3/18
Now you have 3/18 = 1/x
Cross Multiply:
3x = 18
Divide both sides by 3"
x = 18/3
X = 6
It will take both hoses 6 hours.
Given: Principal Amount (P) = $300
The rate of interest (r) = (3/4) compounded quarterly.
No. quarters in 3 years (n) = 3×4 = 12
To find: The amount for the CD on maturity. Let it will be (A)
Formula: Compound Amount (A) = P [ 1 + (r ÷100)]ⁿ
Now, (A) = P [ 1 + (r ÷100)]ⁿ
or, = $300 [ 1 + (3 ÷400)]¹²
or, = $300 × [ 403 ÷ 400]¹²
or, = $300 × 1.0938069
or, = $ 328.14
Hence, the correct option will be C. $328.14
It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.
In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x
2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y
now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
-30-6y+2y=-10 combine like terms
-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5
now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0
and now we have solved the problem. x=0 and y=-5
Answer: He will need to assemble 12 bikes, because 12 x 15.50 = $186 and $186 + 150 = $336
Step-by-step explanation: Don't need one :)) it's basic math
