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Alexxandr [17]
3 years ago
11

Ungrouping 5000 using place value

Mathematics
1 answer:
n200080 [17]3 years ago
8 0
Thou hund ten one
5 , 0 0 0
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NEED The FULL equation. Will give Brainly. Thank you!
Ghella [55]

Answer:

\displaystyle  \sf h( - 1) =   - \frac{    2}{3}

Step-by-step explanation:

we are given a function

\displaystyle \sf h(x) =  \frac{2x - 6}{4 {x}^{2}  + 8}

we would like to simplify it for h(-1)

in order to do so

substitute the value of x

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { (- 1)}^{2}  + 8}

by order of PEMDAS

simplify square:

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { ( 1)}^{}  + 8}

simplify multiplication:

\displaystyle \sf h( - 1) =  \frac{ - 2 - 6}{4 { }^{}  + 8}

simplify addition:

\displaystyle \sf h( - 1) =  \frac{ - 2 - 6}{12}

simplify subtraction:

\displaystyle \sf h( - 1) =  \frac{   - 8}{12}

reduce fraction:

\displaystyle  \sf h( - 1) =   - \frac{    2}{3}

5 0
3 years ago
Let p(n) be the number of primes less than n. What is p(50)
Fofino [41]

Answer:

There are 15 prime numbers less than 50

Step-by-step explanation:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53

8 0
3 years ago
Help fill in the blanks no
DerKrebs [107]

Answer:

Here is the full proof:

AC bisects ∠BCD      Given

∠CAB ≅ ∠CAD          Definition of angle bisector

DC ⊥ AD                    Given

∠ADC = 90°               Definition of perpendicular lines

BC ⊥ AB                    Given

∠ABC = 90°               Definition of perpendicular lines

∠ADC ≅ ∠ABC          Right angles are congruent

AC = AC                     Reflexive property

ΔCAB ≅ ΔCAD          SAA

BC = DC                     CPCTC          

7 0
3 years ago
Yasmin purchased 6 heads of cabbage that each weighed 2 3/8 pounds. How much did the cabbage weigh all together?
nika2105 [10]

Answer:

14\frac{1}{4} pounds

Step-by-step explanation:

Here we have to use multiplication.

Yamin purchased 6 heads of cabbage.

The weight of each cabbage = 2 \frac{3}{8}

First let's convert the mixed fraction 2\frac{3}{8} to improper fraction

2\frac{3}{8} = \frac{19}{8}

The weight of 6 heads of cabbage = 6 x \frac{19}{8}

= 114/8

= 14 \frac{2}{8}

We can reduce 2/8 = 1/4

= 14 \frac{1}{4}

Thank you.

3 0
3 years ago
Dev knows he only has 8 gallons of gasoline in the tank he wants to go on a 300-mile trip will he have to buy more gasoline?
V125BC [204]
No he will not have to buy more gasoline

6 0
3 years ago
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