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sveticcg [70]
3 years ago
15

The difference of two numbers is 8. When twice the first number is added to three times the second number, the result is 51. Wha

t are the two
numbers?
Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0

Answer:

The Answer is: The first number is 15 and the second one is 7.

Step-by-step explanation:

Let f = first number and s = second number

The difference between the two is 8:

f - s = 8

f = 8 + s

Twice the first number plus three times the second number is 51:

2f + 3s = 51

Substitute:

2(8 + s) + 3s = 51

16 + 2s + 3s = 51

16 + 5s = 51

5s = 51 - 16

5s = 35

s = 7, the second number

Find f:

f = 8 + 7 = 15, the first number

Proof:

f - s = 8

15 - 7 = 8

8 = 8

Hope this helps! Have an Awesome Day!! :-)

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Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number
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Answer:

Part a) 2,50,18

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Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For x=2

\sqrt{2}*\sqrt{2}=\sqrt{4}=2 -----> the product is an integer

so

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so

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3) For x=18

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so

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Part B)

1) For x=2

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2) For x=50

\sqrt{50}/\sqrt{2}=\sqrt{25}=5 -----> the result is an integer

3) For x=18

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Therefore

When Jenny divides the square root of her favorite positive integer by \sqrt{2} , she gets an integer

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