what is the equation of the circle with center (0,0) the passes through the point (5,-5). please help

Mathematics

1 answer:

Lunna [17]4 years ago

3 0

<h3>Answer:</h3>

x² + y² = 50

<h3>Step-by-step explanation:</h3>

The circle centered at (h, k) with radius r has equation ...

... (x -h)² + (y -k)² = r²

You have (h, k) = (0, 0), so all we need to do is find r². We can do that by choosing r² so that the equation is true at the given point.

... x² + y² = (5)² + (-5)² = 25 + 25 = 50

Your equation is x² + y² = 50.

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Write an equation of the line that passes through (18,2) and is parallel to the line 3y-x=-12 .

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$y = \frac{1}{3}x-4$

Step-by-step explanation:

<u>Step 1: Solve for y in the first equation</u>

$3y - x = -12$

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$\frac{3y}{3} = \frac{x}{3} - \frac{12}{3}$

$y = \frac{1}{3}x - 4$

<u>Step 2: Determine the important aspects</u>

We know that our line is parallel to the other line that has a slope of 1/3 which means that our slope is also going to be 1/3. We also know that our line crosses the point (18, 2) which means that we can use the point slope form to determine our equation

Point Slope Form → $(y-y_1) = m(x - x_1)$