Explain how you can tell how well a linear or exponential fits a set of data

Mathematics

1 answer:

kotykmax [81]2 years ago

4 0

The coordinates that you record is an example of data from the graph I think

You might be interested in

find a function whose second derivative is y''=12x-2 at each point (x,y) on its graph and y=-x+5 is tangent to the graph at the

pogonyaev

Start by integrating y'' twice to get function y(x).

$y' = \int (12x - 2) dx = 6x^2 -2x + c \\ \\ y = \int (6x^2 -2x+c )dx= 2x^3-x^2 +cx+d$

Next find value of coefficients 'c' and 'd' using the given tangent line
The slope of tangent line is equal to y' when x=1.

$6x^2 -2x+c = -1, x = 1 \\ \\ 6-2+c = -1 \\ \\ c = -5$

The tangent line intersects the curve y(x) when x = 1.
If x = 1, then y = 4 (From y =-x+5)

$y = 2x^3 -x^2-5x +d , x = 1, y = 4 \\ \\ 2-1-5+d = 4 \\ \\ d = 8$

Final Answer:
$y = 2x^3 -x^2 -5x+8$

3 0

2 years ago

Simplify: –3(y + 2)^2 – 5 + 6y

GREYUIT [131]

The answer is -3y^2-6y-17

8 0

2 years ago

Read 2 more answers

One fifth of the employees of Delta Industries, Inc., work in the Southeastern region. If the company employs 252 workers in tha

S_A_V [24]

So, 252 is 1/5 of the total workforce then, the total or whole will then be 5/5 or 1 whole... well, if 252 is 1/5, what's 5/5?

$\bf \begin{array}{ccll}
amount&fraction\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
252&\frac{1}{5}\\\\
x&\frac{5}{5}
\end{array}\implies \cfrac{252}{x}=\cfrac{\frac{1}{5}}{\frac{5}{5}}\implies \cfrac{252}{x}=\cfrac{\frac{1}{5}}{1}\implies \cfrac{252}{x}=\cfrac{1}{5}
\\\\\\
\cfrac{252\cdot 5}{1}=x$

8 0

2 years ago

What are the possible values of x if (4x – 5)2 = 49? Check all that apply. StartFraction negative 4 Over 5 EndFraction StartFrac

kkurt [141]

$(4x - 5)^2 = 49\\x = 3, -\frac{1}{2}$