All categories

3 years ago

How do I combine like terms

1 answer:

5 0

Combining Like Terms Lessons. A term is a constant or a variable in an expression. In the equation 12+3x+2x2=5x-1, the terms on the left are 12, 3x and 2x2, while the terms on the right are 5x, and -1.

You might be interested in

The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management

dexar [7]

Answer:

d. 15

Step-by-step explanation:

Putting the values in the shift 2 function

X1 + X2 ≥ 15

where x1= 13, and x2=2

13+12≥ 15

15≥ 15

At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

Now Putting the value X1 ≥ 12 in shift 2 constraint

X1 + X2 ≥ 15

12+ 2≥ 15

14 ≥ 15

this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

gives

X2 ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

6 0

3 years ago

Find (F/g)(x) F(x) = sqrt x^2-1 g(x) sqrt x-1

Margaret [11]

Answer:

Option A. √(x + 1)

Step-by-step explanation:

Data obtained from the question include:

f(x) = √(x² – 1)

g(x) = √(x – 1)

(f/g) (x) =..?

(x² – 1) => difference of two square

(x² – 1) => (x – 1)(x + 1)

f(x) = √(x² – 1)

f(x) = √(x – 1)(x + 1)

(f/g) (x) = f(x) /g(x)

f(x) = √(x – 1)(x + 1)

g(x) = √(x – 1)

(f/g) (x) = √(x – 1)(x + 1) / √(x – 1)

(f/g) (x) = √[(x – 1)(x + 1) / (x – 1)]

(f/g) (x) = √(x + 1)

7 0

3 years ago

What is the volume of A right prism w/ a triangular base w/ sides of 3,4 and 5 w/ a height of 10?

azamat

Check the picture below.

$\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=&area~of\\ &its~base\\ h=&height\\ \cline{1-2} B=&\frac{1}{2}(3)(4)\\ h=&10 \end{cases}\implies V=\cfrac{1}{3}\cdot \cfrac{1}{2}(3)(4)(10)\implies V=20$

3 0

4 years ago

Please help me with these.. i am stuck

SCORPION-xisa [38]

Answer:

Both are irrational

12√3 = 20.784

9√6 = 22.045

Hopefully this is what you're looking for :)

4 0

3 years ago

In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311

Bingel [31]

Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

$Z_{1-\alpha /2}= Z_{0.975}= 1.965$

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

5 0

4 years ago