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3 years ago

8

In a certain Algebra 2 class of 28 students, 11 of them play basketball and 13 of them play baseball. There are 11 students who

play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

1 answer:

mina [271]3 years ago

3 0

80 + 28 - 13 = 95 + 11 = 106

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HELP PLEASSEEEE I NEED TO FIND THE MISSING SIDE HYPOTENUSE

ZanzabumX [31]

Answer:

B. 6.5

Step-by-step explanation:

You can use the 5 against the unknown number and add a few more moves which makes it 6.5.. It's easier in my head man.

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2 years ago

478 × 965 in distributive property

kakasveta [241]

478(900) + 478(95)

Hope this helps!

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3 years ago

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The standard form of the equation of a circle is (x−5)2+(y−6)2=1.

Crank

Answer:

(A) $x^2+y^2-10x-12y+60=0$

Step-by-step explanation:

The standard form of the equation of a circle is given as:

$(x-5)^2+(y-6)^2=1$

Simplifying the above given equation, we get

$x^2+25-10x+y^2+36-12y=1$

$x^2+y^2-10x-12y+36+25=1$

$x^2+y^2-10x-12y+61=1$

$x^2+y^2-10x-12y+60=0$

which is the required general form of the equation.

Hence, option A is correct.

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3 years ago

Which amount is bigger 9/10 or .71

zhenek [66]

9/10 is bigger. 10/10 is a whole so in decimal 9/10 is .90

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2 years ago

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Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago