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3 years ago

7

Which point is an x-intercept of the quadratic function f(x) = (x – 4)(x + 2)?

1 answer:

Dima020 [189]3 years ago

7 0

Answer:

x = - 2, x = 4

Step-by-step explanation:

Given

f(x) = (x - 4)(x + 2)

To find the x- intercepts let f(x) = 0, that is

(x - 4)(x + 2) = 0 ← in standard form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4 → (4, 0 )

x + 2 = 0 ⇒ x = - 2 → (- 2, 0 )

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soldier1979 [14.2K]

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3 years ago

Sion 5(7 - 4)2 + 3+ 11.

netineya [11]

Answer:

44

Step-by-step explanation:

use the order of operations

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the order of operations is more commonly known as PEMDAS.

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3 0

2 years ago

If m angle A = (4x + 2) degrees , what is the measure of the complement of angle A ?

Kisachek [45]

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3 0

2 years ago

Which of the following equations has a consant of proptionality of 4

EleoNora [17]

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6 0

2 years ago

Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.

Galina-37 [17]

Question:

Prove that:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Answer:

Proved

Step-by-step explanation:

Given

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Required

Prove

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Subtract tan(10) from both sides

$- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

$tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

Factorize the right hand size

$tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)$

Rewrite as:

$tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))$

Divide both sides by $1-tan(70). tan(100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$

In trigonometry:

$tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}$

So:

$\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)}$ can be expressed as: $tan(70 + 100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$ gives

$tan(70 + 100) = -tan(10)$

$tan(170) = -tan(10)$

In trigonometry:

$tan(180 - \theta) = -tan(\theta)$

So:

$tan(180 - 10) = -tan(10)$

Because RHS = LHS

Then:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$ has been proven

6 0

2 years ago