Your list of numbers needs a bit of clarification.
You wrote: <span>.9,1.1,.10 38 and .10299
I have to make some assumptions here, and to ask whether you meant the following:
</span><span>.9, 1.1, .1038 and .10299
If so, now's the time to look for the smallest and the largest of these numbers. The smallest is 0.10299:
smallest
</span>
0.10299
<span>0.1038
0.9
1.1
</span>.9, 1.1, .1038 and .10299
If my list disagrees with yours, please ensure that you have copied down these four numbers correctly and then try again (on your own) to order them correctly from smallest to largest.
The margin of error of the random selection is 0.29
The given parameters are:
--- the sample size
--- the standard deviation
--- the mean
--- the confidence level.
The margin of error (E) is calculated as follows:
So, we have:
The z-value for 90% confidence level is 1.645.
Substitute 1.645 for z
Take square roots
Multiply
Approximate
Hence, the margin of error is 0.29
Read more about margin of error at:
brainly.com/question/14396648
Answer:
To complete the required $m dollars for her college, she needs $(m - 60,000).
Step-by-step explanation:
Suppose Rebecca needs $m to complete her college education,
because she has a yearly scholarship of $10,000, she would have $10,000 × 4 = $40,000 for the four years she would spend in college.
Together with her savings of $20,000, she has $20,000 + $40,000 = $60,000 in total.
Therefore to complete the required $m dollars for her college, she needs $(m - 60,000).
Answer:
-206675344746
Step-by-step explanation:
1000*0+321*15678*9(-4563) = -206675344746
It would be considered to be around 0 37
