which equation models the same quadratic relationship as function f? f(x)=x^2+12x+4 a) y=(x-6)^2+40 b) y=(x+6)^2-32 c) y=(x-6)^2
-32 d) y=(x+6)^2+40
2 answers:
9514 1404 393
Answer:
b) y=(x+6)^2-32
Step-by-step explanation:
Add and subtract the square of half the x-coefficient to put into vertex form.
f(x) = x^2 +12x +4 . . . . . given
y = x^2 +12x +36 +4 -36 . . . . add and subtract (12/2)^2 = 36
y = (x +6)^2 -32 . . . . . . . . . . . write in vertex form
Answer:
<h2>B. Y=(x+6)²-32</h2>
Step-by-step explanation:
hope it helps
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