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denis-greek [22]

3 years ago

5

Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa

rameter. x = 5 + ln(t), y = t2 + 1, (5, 2)

1 answer:

liubo4ka [24]3 years ago

4 0

Im sorry i need points , i am really sorry

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Pls help! Show all work. Will reward the brainiest for da best answer.

BaLLatris [955]

Answer:

1. 56.52 inches

2. 141,300 inches

Step-by-step explanation:

One turn of the tire is the circumference. Therefore, we have to find the circumference first. C = πd = 18π = 18 × 3.14 = 56.52 in

2500 rotations would be 2500 ⋅ 56.52 in = 141,300 in

I hope this helps and please mark me as brainliest!

4 0

2 years ago

1/4 a = 4/15<br><br> I’ll add extra points show ur sork

alexandr402 [8]

Answer:16/15

Step-by-step explanation:

5 0

2 years ago

Which points are collinear with A and N?

stepan [7]

Collinear points lie on the same line. So, you must look for other points that lie on the line that connects A and N. If you start from A and continue along that line, you can see that, after N, you will meet points M and F.

So, those points are collinear with A and N.

4 0

3 years ago

Can you square a negative number

chubhunter [2.5K]

Yes, you can square a negative, however it can only give you a positive answer

however, you cannot root a negative number (if that was what you wanted)

hope this helps

3 0

3 years ago

Read 2 more answers

blagie [28]

$\mathcal \pink{GIVEN:}$

<em><u>Radius</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>m</u></em>
<em><u>Height</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u> </u></em><em><u>m</u></em>

<em><u> $\mathcal \purple{TO \: FIND:}$ </u></em>

<em><u>Volume</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>?</u></em>

<em><u> $\mathcal \blue{CALCULATION:}$ </u></em>

$\qquad{ \sf \: volume = \pi{r}^{2}h }$

Where,

r is radius
h is height

$\qquad{ \tt\nrightarrow \: \frac{22}{7} \times {3}^{2} \times 7}$

$\qquad{ \tt\nrightarrow \: \frac{22}{ \cancel7} \times {3}^{2} \times \cancel7}$

$\qquad{ \tt\nrightarrow \: 22 \times {3}^{2} }$

$\qquad{ \tt\nrightarrow \: 22 \times 9 }$

$\qquad{ \boxed{ \tt\Rrightarrow \: 198\: {m}^{3} }}$

➪ <em>H</em><em>e</em><em>n</em><em>c</em><em>e</em><em>f</em><em>o</em><em>r</em><em>t</em><em>h</em><em>,</em><em> </em><em>T</em><em>h</em><em>e</em><em> </em><em>v</em><em>o</em><em>l</em><em>u</em><em>m</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>cylinder</em><em> </em><em>i</em><em>s</em><em> </em><em>1</em><em>9</em><em>8</em><em> </em><em>m</em><em>³</em><em>.</em><em>.</em><em>.</em>

6 0

2 years ago