1 year ago

The length of one leg of an isosceles right triangle is 3 ft. What is the perimeter of the triangle?

Mathematics

1 answer:

ExtremeBDS [4]1 year ago

6 0

Check the picture below.

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T=76

Step-by-step explanation:

If the formula is T=50+N-40 and N=66 then you just substitute 66 in for N then you have T=50+66-40 where as T=76

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Julie works for 48 hours per week for 12 weeks during the summer, making $5000. If she works for 48 weeks during the school year

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She would need to work 12 hours per week.

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3 years ago

I have a question in math, will give brainliest

iris [78.8K]

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2 years ago

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A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui

Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= $\frac{dx}{dt}=1. 8 m/s$

$\triangle ABD\sim\triangle ECD$

Therefore, $\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{y}{2}=\frac{12}{x}$

$xy=24$

Differentiate w.r.t t

$x\frac{dy}{dt}+y\frac{dx}{dt}=0$

$x\frac{dy}{dt}=-y\frac{dx}{dt}$

$\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}$

When the man is 4 m from the building

Then, we have x=12-4=8 m

$\frac{dx}{dt}=1.8 m/s$

Substitute the values in above equation then, we get

$8y=24$

$y=\frac{24}{8}=3$

Substitute the values then we get

$\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s$

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

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3 years ago

A(n)=-6+3(n-1). Find the 16th term in the sequence

marshall27 [118]

Answer:

16th term = 39.

Step-by-step explanation:

Plug 16 into the formula -6 + 3(n - 1):

A(16) = -6 + 3(16-1)

= - 6 + 3*15

= -6 + 45

= 39.

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2 years ago

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