Ask question

Ask question

All categories

2 years ago

12

while shopping for clothes, Tracy spent $38 less than 3 times what Daniel spent. write and solve an equation to find how much Da

niel spent.

2 answers:

lana [24]2 years ago

5 0

Answer: $3x - 38$

Step-by-step explanation:

Let, Tracy spent in the cloths = $ x

Tracy spent $38 less than 3 times what Daniel spent

$\implies \text{ Daniel spent in the cloths} = 38 - 3 \times \text{ Tracy's spending in the cloths}$

= $38 - 3 x$

Which is the required expression of Daniel spending on the cloth.

zzz [600]2 years ago

3 0

Answer:

Daniel spent $\frac{1}{3}$ times 38 more than Tracy.

Step-by-step explanation:

Given that Tracy spent $38 less than 3 times what Daniel spent.

we have to find out the equation for how much Daniel spent

Let Daniel spent $x

Given that Tracy spent $38 less than 3 times what Daniel spent.

∴ Tracy spent= $(3x-38)

Solve for x is

3x=Tracy spent + 38

⇒ $x=\frac{Tracy spent+38}{3}Hence, Daniel spent [tex]\frac{1}{3}$ times 38 more than Tracy.

You might be interested in

Express 0.52 as a fraction

ioda

52/100
26/50
13/25
These will all do.

7 0

3 years ago

Read 2 more answers

tanya purchased 4 hamners for $11.00 each and 7 scewdrivers for $6.65 each write an expresion for the total cost of the tools.th

rewona [7]

X=numbers of hammers
y=numbers of scewdrivers
f(x,y)= total cost in $

f(x,y)=11x+6.65y

f(4,7)=4(11)+6.65(7)=44+46.55=90.55

Sol: an expresion for the total cost of the tools is f(x,y)=11x+6.65 y;
x=number of hammers
y= number of scewdrivers.
The total cost is $90.55

7 0

3 years ago

Read 2 more answers

Adding the fractions<br><br> 3/14+2/21+1/6

NARA [144]

Answer:

$\frac{10}{21}$

Step-by-step explanation:

The LCM of 14, 21 and 6 is 42

We require to change the fractions to fractions with a denominator of 42

$\frac{3(3)}{14(3)}$ + $\frac{2(2)}{21(2)}$ + $\frac{1(7)}{6(7)}$

= $\frac{9}{42}$ + $\frac{4}{42}$ + $\frac{7}{42}$ ← add the numerators, leaving the denominator

= $\frac{9+4+7}{42}$

= $\frac{20}{42}$ ← divide both values by 2

= $\frac{10}{21}$ ← in simplest form

6 0

2 years ago

A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

So

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0

3 years ago

Find an equation for the line perpendicular to 2x+ 6y = 30 and goes through the point (6,2)

Mashutka [201]

Answer:

y = 3x - 16

Step-by-step explanation:

We are asked to find the equation of the line perpendicular to 2x + 6y = 30

We can use two formulas for this question, either

y = mx + c. Or

y - y_1 = m(x - x_1)

Step 1: calculate the slope

From the equation given

2x + 6y = 30

Make y the subject of the formula

6y = 30 - 2x

Or

6y = -2x + 30

Divide both sides by 6, to get y

6y/6 = ( -2x + 30)/6

y = (-2x + 30)/6

Separate them in order to get the slope

y = -2x/6 + 30/6

y = -1x/3 + 5

y = -x/3 + 5

Slope = -1/3

Step 2:

Note: if two lines are perpendicular to the other, both are negative reciprocal of each other

Perpendicular slope = 3/1

Substitute the slope into the equation

y = mx + c

y = 3x + c

Step 3: substitute the point into the equation

( 6,2)

x = 6

y = 2

2 = 3(6) + c

2 = 18 + c

Make the c the subject

2 - 18 =c

c = 2 - 18

c = -16

Step 4: sub the value of c into the equation

y = 3x + c

y = 3x - 16

The equation of the line is

y = 3x - 16

If you try out the other formula, u will get the same answer

5 0

3 years ago