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Assoli18 [71]
3 years ago
7

Please send the solution​

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

Please use photomath haha

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Brainliest if you provide an explanation and/or get it right!
vaieri [72.5K]
Y=1.75(3)

y=5.25

Hope this helps!! You just have to plug 3 in for x
4 0
3 years ago
What is the equation of a horizontal line passing through the point (−7, 5)? (1 point)
netineya [11]
If it’s a horizontal line, we focus on the y-coordinates.

(-7,5)

-7 is a x-coordinate
5 is a y-coordinate


The answer is y = 5
6 0
3 years ago
You have to spend money to make money ! You purchase a mix of newspaper ads and online ads. Each newspaper ad cost $18.50 and ea
SpyIntel [72]

Answer:

You buy six newspaper ads & eighteen social media ads.

Step-by-step explanation:

First, we change ads into variables to be more easier to calculate :

Let newspaper = x

Let social media = y

Second, make this variables into an equation, given that you purchase a total of 24 ads :

x + y = 24 (first equation)

Next, given that x = $18.50 & y = $26.50 & spent a total of $588 so you can make another equation :

18.50x + 26.50y = 588 (second equation)

Now, solve this simultaneous equation using elimination or substitution (depends on you) :

substitution =>

x + y = 24 ----------(1)

18.50x + 26.50y = 588 ---------(2)

(1)=> y = 24 - x ------(3)

(3)=>(2) 18.5x + 26.5(24-x) = 588

18.5x + 636 - 26.5x = 588

-8x = -48

x = 6

sub x=6 into(3)

(3)=> y = 24 - 6

= 18

newspaper = x

= 6

social media = y

= 18

6 0
3 years ago
There are 90 passengers on a commuter flight from SFO to LAX, of whom 27 are traveling on business. In a random sample of five p
stepladder [879]

Answer:

C). 0.83193

Step-by-step explanation:

There are total of 90 passengers of which 27 are for business.

The probability of passengers for business = 27/90

The probability of passengers for business p = 0.3

The probability of passengers not for business q = 1-The probability of passengers for business

= 1-0.3

= 0.7

Random sample of 5 passenger, probability of at least one business passenger = 1 - probability of no business passenger

probability of no business passenger

= 5C0(0.3)^0 * (0.7)^5

= 1 *1*0.16807

= 0.16807

probability of at least one business passenger = 1 - probability of no business passenger

= 1-0.16807

=0.83193

4 0
3 years ago
Y+1=3(x-4)y+1=3(x−4) find the slope
julia-pushkina [17]

Answer:

0

y+1= (3x-12)y+1=3x-12

7 0
3 years ago
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