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3 years ago

9

What is the slope of the line described by the equation below? Y - 5= -3(x - 17)

2 answers:

MA_775_DIABLO [31]3 years ago

7 0

Hello there!

To find the slope, we must first put this equation in y = mx + b form (also known as slope intercept form)

First, let's solve the right side using the distributive property.

To do this, we will multiply -3 by both x and -17

-3 * x = -3x

-3 * -17 = 51 (a negative times a negative equals a positive)

So, now we have: y - 5 = -3x + 51

Now we must get rid of the -5 on the right side.

To do this, we will add -5 to both sides

y - 5 + 5 = -3x + 51 + 5

Now we have y = -3x + 56

Now, we know the slope is -3

I hope my answer helped you out!

~ Fire

Alenkinab [10]3 years ago

4 0

First distribute -3 to both x and -17
-3(x) = -3x
-3(-17) = 51

y - 5 = -3x + 51

isolate the y, add 5 to both sides

y - 5 (+5) = -3x + 51 (+5)

add all numbers with same variables together

y = -3x + 51 + 5
y = -3x + 56

inside the slope intercept form:

y = y
m = slope
x = x
b = intercept.

y = mx + b (using this equation, we can see that -3 = m)

-3 is slope, and is your answer

hope this helps

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$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

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d.f.D = N - k

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$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

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The grand mean or the overall mean is(GM) :

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The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

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The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

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The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

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Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

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