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Elan Coil [88]
3 years ago
12

If you could switch two movie characters, what switch would lead to the weirdest movies?​

Mathematics
2 answers:
Viefleur [7K]3 years ago
8 0

Answer:

Dwyane Johnson and Prison Welles

Step-by-step explanation:

The rock being an Action, adventure. movies star playing Orson's classic characters in his films like Othello or Citizen Kane?

To some, who like the classic English literature films, Orson was a brilliant actor.

The rock. is by no means a star but, not in Orson's character method acting.

Leviafan [203]3 years ago
6 0

Answer:

Switching the Beast from Beauty and the Beast with Ariel From the Little Mermaid.

Step-by-step explanation:

Imagine the Beast being a merman o-o

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Associative property under multiplication.

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15v − -14v − -14 = -15 solve for v ps..... help plz
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Solve for  v  by simplifying both sides of the equation, then isolating the variable.

v = -1

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A quadratic function has a vertex of (0,7) and passes through the point (2, 3). Which of
Arlecino [84]

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Y = -2X + 7

Step-by-step explanation:

Y = a(x-h)^2 + k

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3 = a(2-0) + 7

3 = 2a - 0 + 7

Collect like terms

2a = 3 - 7

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Divide both sides by 2

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2 years ago
3-(-6/7)(3/8) what will it equal?
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4 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
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